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adell [148]
3 years ago
7

Question #6

Physics
1 answer:
Novay_Z [31]3 years ago
4 0

The two points on a periodic wave in a medium are said to be in phase if they have the same amplitude and are moving in the same direction.

Option 4.

Explanation:

A periodic wave is termed for waves which flow in a repetition pattern in a given time scale. Periodic wave can also be termed as a transverse wave. So a transverse wave have various crests and troughs. The two successive crests and two successive troughs are said to be in phase with each other.

Thus, for a periodic wave in a medium, the in phase can be obtained in two points which have the same amplitude and are moving in the same direction.

As amplitude is a scalar quantity and so direction should be taken into consideration for making the points related to successive crests only in phase with themselves. Also this also relates the points related to successive troughs to be in phase with each other. But a crest and a trough will not be in phase with each other.

Thus, option 4, that is the two points on a periodic wave in a medium are said to be in phase if they have the same amplitude and are moving in the same direction.

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Answer:

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A car moving with a speed of 35 m/s sees a child standing in the
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Answer:

2100 N

Explanation:

v = u + at \\ 0 = 35 + a(5) \\ a =  - 7m {s}^{ - 2}  \\ \\ net \: force \:  = ma \\  = (300)(7) \\  = 2100 \: newtons

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What best explains whether bromine (Br) or neon (Ne) is more likely to form a covalent bond? On left, a purple circle labeled Br
blondinia [14]

Answer:

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Explanation:

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3 years ago
Four traveling waves are described by the following equations, where all quantities are measured in SI units and y represents th
agasfer [191]

Answer:

T_1=T_3=\dfrac{2\pi}{21}

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Explanation:

Wave 1, y_1=0.12\ cos(3x-21t)

Wave 2, y_2=0.15\ sin(6x+42t)

Wave 3, y_3=0.13\ cos(6x+21t)

Wave 4, y_4=-0.27\ sin(3x-42t)

The general equation of travelling wave is given by :

y=A\ cos(kx\pm \omega t)

The value of \omega will remain the same if we take phase difference into account.

For first wave,

\omega_1=21

\dfrac{2\pi }{T_1}=21

T_1=\dfrac{2\pi}{21}

For second wave,

\omega_2=42

\dfrac{2\pi }{T_2}=42

T_2=\dfrac{2\pi}{42}

For the third wave,

\omega_3=21

\dfrac{2\pi }{T_3}=21

T_3=\dfrac{2\pi}{21}

For the fourth wave,

\omega_4=42

\dfrac{2\pi }{T_4}=42

T_4=\dfrac{2\pi}{42}

It is clear from above calculations that waves 1 and 3 have same time period. Also, wave 2 and 4 have same time period. Hence, this is the required solution.

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when the driver of a car applies the brakes a force of 4000N brings the car to a stop over a distance of 50m.calculate the work
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W = 200KJ

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