parabolic motion
![\tt t_{max}=\dfrac{2u~sin~\alpha }{g}](https://tex.z-dn.net/?f=%5Ctt%20t_%7Bmax%7D%3D%5Cdfrac%7B2u~sin~%5Calpha%20%7D%7Bg%7D)
![\tt h_{max}=\dfrac{u^2sin^2\alpha }{2g}](https://tex.z-dn.net/?f=%5Ctt%20h_%7Bmax%7D%3D%5Cdfrac%7Bu%5E2sin%5E2%5Calpha%20%7D%7B2g%7D)
vertically upwards ⇒ α = 90°⇒sin 90° = 1
![\tt 4=\dfrac{2u}{10}\rightarrow u=20~m/s](https://tex.z-dn.net/?f=%5Ctt%204%3D%5Cdfrac%7B2u%7D%7B10%7D%5Crightarrow%20u%3D20~m%2Fs)
![\tt h_{max}=\dfrac{20^2}{2.10}=\boxed{\bold{20~m}}](https://tex.z-dn.net/?f=%5Ctt%20h_%7Bmax%7D%3D%5Cdfrac%7B20%5E2%7D%7B2.10%7D%3D%5Cboxed%7B%5Cbold%7B20~m%7D%7D)
Explanation:
In brief, electrons are negative charges and protons are positive charges. An electron is considered the smallest quantity of negative charge and a proton the smallest quantity of positive charge.
Two negative charges repel. Also, two positive charges repel. A positive charge and a negative charge attract each other (all experimentally verified.)
Point Charge: An accumulation of electric charges at a point (a tiny volume in space) is called a point charge.
Note: When an atom loses an electron, the separated electron forms a negative charge, but the remaining that contains one less electron or consequently one more proton becomes a positive charge. A positive charge is not necessarily a single proton. In most cases, a positive charge is an atom that has lost one or more electron(s).
Answer:
The constant force is 263.55 newtons
Explanation:
There's a rotational version of the Newton's second law that relates the net torque on an object with its angular acceleration by the equation:
(1)
with τ the net torque and α the angular acceleration. It’s interesting to note the similarity of that equation with the well-known equation F=ma. I that is the moment of inertia is like m in the linear case. The magnitude of a torque is defined as
![\tau = Fr\sin \theta](https://tex.z-dn.net/?f=%20%5Ctau%20%3D%20Fr%5Csin%20%5Ctheta)
with F the force applied in some point, r the distance of the point respect the axis rotation and θ the angle between the force and the radial vector that points toward the point the force is applied, in our case θ=90 and sinθ=1, then (1):
(2)
Because the applied force is constant the angular acceleration is constant too, and for constant angular acceleration we have that it's equal to the change of angular velocity over a period of time:
![\alpha=\frac{0.800}{2.00}=0.40 \frac{rev}{s^{2}}](https://tex.z-dn.net/?f=%20%5Calpha%3D%5Cfrac%7B0.800%7D%7B2.00%7D%3D0.40%20%5Cfrac%7Brev%7D%7Bs%5E%7B2%7D%7D)
It's important to work in radian units so knowing that ![1rev=2\pi rad](https://tex.z-dn.net/?f=1rev%3D2%5Cpi%20rad%20)
(3)
The moment of inertia of a disk is:
(4)
with M the mass of the disk and R its radius, then
![I=\frac{(140)(1.50)^{2}}{2}=157.5 kg*m^2](https://tex.z-dn.net/?f=I%3D%5Cfrac%7B%28140%29%281.50%29%5E%7B2%7D%7D%7B2%7D%3D157.5%20kg%2Am%5E2%20)
using the values (3) and (4) on (2)
(2)
Because the force is applied about the rim of the disk r=R=1.50:
![F= \frac{(157.5)(2.51)}{1.50}=263.55 N](https://tex.z-dn.net/?f=%20F%3D%20%5Cfrac%7B%28157.5%29%282.51%29%7D%7B1.50%7D%3D263.55%20N)
I think it will go down like decrease minus or whatever you call it