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kenny6666 [7]
3 years ago
7

Describe how day length is affected by the tilt of the earths axis

Physics
1 answer:
igor_vitrenko [27]3 years ago
7 0

It does not.

The speed at which the earth rotates determines the length of the day.


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What does gravity determine?
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the amount of friction A
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Directions: Fill in the blank with the correct word. Choose from the list of possible answers in the word bank below:
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Answer:

1).atoms (3). mixture. (5). Element

2). particles (4). molecules (6). suspension

Explanation:

(7). Homogeneous (8). Heterogeneous

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3 years ago
A ray diagram is shown. what does the letter x represent?
kobusy [5.1K]

Answer: Letter X in the diagram represent the angle of incidence

Explanation: One of the properties of wave is reflection. But before reflection can occur, there must have been a directed motion of wave particle towards a plane surface. The angle of incidence is the angle between the direction of motion of the wave particle ( for example; light) and the normal to the plane surface.

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A horizontal pipe 18.0 cm in diameter has a smooth reduction to a pipe 9.00 cm in diameter. If the pressure of the water in the
Rzqust [24]

Answer:

The rate of flow of water is 71.28 kg/s

Solution:

As per the question:

Diameter, d = 18.0 cm

Diameter, d' = 9.0 cm

Pressure in larger pipe, P = 9.40\times 10^{4}\ Pa

Pressure in the smaller pipe, P' = 2.80\times 10^{4}\ Pa

Now,

To calculate the rate of flow of water:

We know that:

Av = A'v'

where

A = Cross sectional area of larger pipe

A' = Cross sectional area of larger pipe

v = velocity of water in larger pipe

v' = velocity of water in larger pipe

Thus

\pi \frac{d^{2}}{4}v = \pi \frac{d'^{2}}{4}v'

18^{2}v = 9^v'

v' = 4v

Now,

By using Bernoulli's eqn:

P + \frac{1}{2}\rho v^{2} + \rho gh = P' + \frac{1}{2}\rho v'^{2} + \rho gh'

where

h = h'

\rho = 10^{3}\ kg/m^{3}

9.40\times 10^{4} + \frac{1}{2}\rho v^{2} = 2.80\times 10^{4} + \frac{1}{2}\rho (4v)^{2}

6.6\times 10^{4}  = \frac{1}{2}\rho 15v^{2}

v = \sqrt{\frac{2\times 6.6\times 10^{4}}{15\times 10^{3}}} = 8.8\ m/s

Now, the rate of flow is given by:

\frac{dm}{dt} = \frac{d}{dt}\rho Al = \rho Av

\frac{dm}{dt} = 10^{3}\times \pi (\frac{18}{2}\times 10^{- 2})^{2}\times 8.8 = 71.28\ kg/s

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I need help with question 8 and 9
Wewaii [24]

8) The height of the shelf is 2.04 m

9) The gravitational potential energy is 100 J

Explanation:

8)

The gravitational potential energy of an object is given by:

PE=mgh

where

m is the mass of the object

g is the acceleration of gravity

h is the heigth of the object, relative to the ground

For the object in this problem, we have

m = 10 kg

g=9.8 m/s^2

And we know that

PE = 200 J

Therefore we can re-arrange the formula to solve for h, the heigth of the object:

h=\frac{PE}{mg}=\frac{200}{(10)(9.8)}=2.04 m

9)

As before, the gravitational potential energy of the object is given by:

PE=mgh

where in this  case, we have:

m = 10 kg is the mass of the object

h = 2.04 m is the height of the object from the ground

While in this case, the acceleration of gravity on this planet is

g=4.9 m/s^2

Substituting,

PE=(10)(4.9)(2.04)=100 J

Learn more about potential energy:

brainly.com/question/1198647

brainly.com/question/10770261

#LearnwithBrainly

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