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sergij07 [2.7K]
3 years ago
6

3 Ca + 2 AICI3 + 3 CaCl2 + 2 AI

Chemistry
1 answer:
Olenka [21]3 years ago
4 0

Answer:

249.44g of CaCl2

Explanation:

First, we need to write a balanced equation for the reaction. This is illustrated below:

2AlCl3 + 3Ca —> 3CaCl2 + 2Al

Molar Mass of AlCl3 = 27 + (3x35.5) = 27 + 106.5 = 133.5g/mol

Mass of AlCl3 from the balanced equation = 2 x 133.5g = 267g

Molar Mass of CaCl2 = 40 + (2 x 35.5) = 40 + 71 = 111g/mol

Mass of CaCl2 from the balanced equation = 3 x 111 = 333g

From the equation,

133.5g of AlCl3 produced 333g of CaCl2

Therefore, 100g of AlCl3 will produce = (100 x 333)/133.5 = 249.44g of CaCl2.

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3 years ago
Rotation about a carbon-carbon double bond does not readily occur because: __________.1) the overlap of the p orbitals of the ca
Advocard [28]

Answer:

1) The overlap of the p orbitals of the carbon-carbon π bond would be lost

Explanation:

Unlike simple bonds, a double bond can not rotate, since it is not possible to twist the ends of the molecule without breaking the π bond.

In the structure of but-2-ene present in the attachment, we can see the two isomers, <em>cis</em> and<em> trans</em>. These isomers cannot be interconverted by rotation around the carbon-carbon double bond without breaking the π bond.

5 0
3 years ago
What is the cost of carbon in gram
Morgarella [4.7K]
Carbon is 12 grams per mole
6 0
3 years ago
A 232 mL cup of whole milk contains about 27 mg of cholesterol. Express the cholesterol concentration of the milk in kilograms p
son4ous [18]

Explanation:

Cholesterol concentration = 27 mg/ 232 mL

Change unit mg/ml to kg/m³

1 kg = 1000 g

1 g = 1000 mg

1 kg = 1000000 mg

1 kg = 10⁶ mg

10⁶ mg = 1 kg

1 mg = 10^-6 kg

m³ = 1000 L

1 L = 1000 mL

m³ = 1000000 mL

m³ = 10⁶ mL

10⁶ mL = m³

1 mL = 10^-6 m³

Cholesterol concentration = 27 mg/ 232 mL

27 × 10^-6 kg/ 232 × 10^-6 m³

= 27/232 kg/m³

6 0
3 years ago
PLEASE SOMEBODY EXPLAIN THIS :(((
djverab [1.8K]

Answer:

\boxed{ \sf \: R_f  \: value \: of \: sample \: 1 =0.3142}

<h3>Explanation:</h3>

In Analytical Chemistry chromatography is widely used for the separation of samples.

  • In thin layer chromatography, the mixture of components are separated on the basis of their polarity.
  • The solvent solution(mobile phase) that we use are non polar & silica gel( TLC paper made of/stationary phase) are polar.
  • Consider the mixture we have taken consist of two samples having large polar difference.
  • Due to opposite nature of silica gel(polar) & solvent solution (non polar) the movement become easy & due to capillary action solvent solution rise to the top.
  • The mixture of sample we have taken, the sample have less polarity have high peak or they travel more distance than that of more polar sample when they dipped into the solution.

In the given diagram, mixture of 8 samples are separated on the basis of their polarity, the distance travelled by solvent is 35 mm, distance travelled by sample 1 is 11 mm & similarly distance travelled by sample 2,3,4,5,6,7 are 15,31,4,22,25,33 in mm respectively.

Rf Value: Rf value is retention factor which tells about relative absorption of each sample & range of Rf value is 0-1.

Formula to calculate Rf value is

\sf R_f  \: value = \frac{distance \: moved \: by \: sample}{distance \: moved \: by \: solvent}

Now, solving for Rf value of sample 1

<em>Given:</em>

Distance moved by sample 1 = 11 mm

Distance movedby solvent = 35 mm

<em>To find:</em>

Rf value of sample 1 = ?

<em>Solution:</em>

Substituting the given data in above formula,

\small \sf R_f  \: value = \frac{distance \: moved \: by \: sample \: 1}{distance \: moved \: by \: solvent}   \\  \small \sf R_f  \: value =  \cancel\frac{11  \: mm}{35 \:  mm}  = 0.3142

\small \boxed{ \sf \: R_f  \: value \: of \: sample \: 1 =0.3142}

<em><u>Thanks for joining brainly community!</u></em>

4 0
3 years ago
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