Question

3 Ca + 2 AICI3 + 3 CaCl2 + 2 AI

Answer 1

Answer:

249.44g of CaCl2

Explanation:

First, we need to write a balanced equation for the reaction. This is illustrated below:

2AlCl3 + 3Ca —> 3CaCl2 + 2Al

Molar Mass of AlCl3 = 27 + (3x35.5) = 27 + 106.5 = 133.5g/mol

Mass of AlCl3 from the balanced equation = 2 x 133.5g = 267g

Molar Mass of CaCl2 = 40 + (2 x 35.5) = 40 + 71 = 111g/mol

Mass of CaCl2 from the balanced equation = 3 x 111 = 333g

From the equation,

133.5g of AlCl3 produced 333g of CaCl2

Therefore, 100g of AlCl3 will produce = (100 x 333)/133.5 = 249.44g of CaCl2.