4 years ago

How many mL of 4.0% Mg(NO3)2 solution would contain 1.2 g of magnesium nitrate?

1 answer:

galina1969 [7]4 years ago

8 0

4.0 % in mass per volume :

4.0 g ---------- 100 mL
1.2 g ---------- ( volume )

Volume = 1.2 x 100 / 4.0

Volume = 120 / 4.0

= 30 mL

hope this helps!

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