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solmaris [256]
3 years ago
13

How many mL of 4.0% Mg(NO3)2 solution would contain 1.2 g of magnesium nitrate?

Chemistry
1 answer:
galina1969 [7]3 years ago
8 0
4.0 % in mass per volume :

4.0 g ---------- 100 mL
1.2 g ----------  ( volume )

Volume =  1.2 x 100 / 4.0

Volume = 120 / 4.0

= 30 mL

hope this helps!
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