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3 years ago

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Satellite A revolves around Earth 5 times a day. What is the radius of its orbit, measured from Earth's center? Assume that Eart

h generates the only significant gravitation attraction on the satellite. Note: The mass of Earth is 5.98 × 1024 kg, and the constant of universal gravity (G) equals 6.674 × 10-11 N · m2/kg2.
0.69 × 107 m

7.22 × 107 m

2.11 × 107 m

1.44 × 107 m

1 answer:

sasho [114]3 years ago

5 0

Answer: 1.44. You can set centripetal force equal to gravitational force caused by the earth because the grav. force is what causes the satellite to orbit in a circle

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astronauts in space cannot weigh themselves by standing on a bathroom scale. Instead, they determine their mass by oscillating o

devlian [24]

Answer:

The right answer is:

(a) 63.83 kg

(b) 0.725 m/s

Explanation:

The given query seems to be incomplete. Below is the attachment of the full question is attached.

The given values are:

T = 3 sec

k = 280 N/m

(a)

The mass of the string will be:

⇒ $T=2 \pi\sqrt{\frac{m}{k} }$

or,

⇒ $m=\frac{k T^2}{4 \pi^2}$

On substituting the values, we get

⇒ $=\frac{280\times (3)^2}{4 \pi^2}$

⇒ $=\frac{280\times 9}{4\times (3.14)^2}$

⇒ $=68.83 \ kg$

(b)

The speed of the string will be:

⇒ $\frac{1}{2}k(0.4)^2=\frac{1}{2}k(0.2)^2+\frac{1}{2}mv^2$

then,

⇒ $v=\sqrt{\frac{k((0.4)^2-(0.2)^2)}{m} }$

On substituting the values, we get

⇒ $=\sqrt{\frac{280\times ((0.4)^2-(0.2)^2)}{63.83} }$

⇒ $=\sqrt{\frac{280(0.16-0.04)}{63.83} }$

⇒ $=\sqrt{\frac{280\times 0.12}{63.83} }$

⇒ $=0.725 \ m/s$

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3 years ago

When an alkali metal is involved in a chemical reaction with a nonmetal, what charge will its atoms most likely form? 1- 2- 2+ 1

seraphim [82]

Answer:

+1 ion

Explanation:

Alkali metals are metals that are found in Group I of the periodic table. Their electronic configuration is such that their valence shell in grounds state is always holding only one electron which they always lose when reacting with non-metals. A loss in an electron makes the atom electrically imbalanced and hence becoming a +1 ion.

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A stable, binary ionic compound exists where the cation (A) has a charge twice in magnitude than that of the anion (X). What wou

svetlana [45]

<span>The cation is positively charged and has a charge twice that of the anion, for example +2. The anion is negatively charged and in our example where the cation has a +2 charge, it must have a -1 charge. In order for the charges to equal zero, there must be two anions: -1 x 2 = -2 So the answer is D. AX2</span>

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3 years ago

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Review. As an astronaut, you observe a small planet to be spherical. After landing on the planet, you set off, walking always st

anyanavicka [17]

To find the mass of the planet we will apply the relationship of the given circumference of the planet with the given data and thus find the radius of the planet. From the kinematic equations of motion we will find the gravitational acceleration of the planet, and under the description of this value by Newton's laws the mass of the planet, that is,

The circumference of the planet is,

$\phi = 25.1m$

Under the mathematical value the radius would be

$\phi = 2\pi r$

$r = \frac{25}{2\pi}$

$r = 3.9788km$

Using second equation of motion

$x = \frac{1}{2} at^2$

Replacing the values given,

$1.4 = \frac{1}{2} a (29.2)^2$

Rearranging and solving for 'a' we have,

$a = 0.003283m/s^2$

Using the value of acceleration due to gravity from Newton's law we have that

$a = \frac{GM}{r^2}$

Here,

r = Radius of the planet

G = Gravitational Universal constant

M = Mass of the Planet

$\frac{(6.67*10^{-11})*M}{(3.9788*10^3)^2} = 0.003283$

$M = 7.79201*10^{14}kg$

Therefore the mass of this planet is $7.79201*10^{14}kg$

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3 years ago

KATZPSEF1 30.P.041. My Notes Ask Your Teacher A charged particle enters a region of space with a uniform magnetic field B = 1.98

sladkih [1.3K]

Answer: The charge on the particle is positive

While the magnitude = 0.00028C

Explanation:

Please find the attached file for the solution

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