To fully understand the problem, we use the ICE table to identify the concentration of the species. We calculate as follows:
Ka = 2.0 x 10^-9 = [H+][OBr-] / [HOBr]
HOBr = 0.50 M
KOBr = 0.30 M = OBr-
<span> HOBr + H2O <-> H+ + OBr- </span>
<span>I 0.50 - 0 0.30 </span>
<span>C -x x x
</span>---------------------------------------------
<span>E(0.50-x) x (0.30+x) </span>
<span>Assuming that the value of x is small as compared to 0.30 and 0.50 </span>
<span>Ka = 2.0 x 10^-9 = x (0.30) / 0.50) </span>
<span>x = 3.33 x 10^-9 = H+</span>
pH = 8.48
Answer: the molecular altatude of the supercalifragilistic gene should expand by 100%,
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Explanation:
2HCL + __ Zn --> ZnCl2 + H2
i think that's right, not exactly sure.
I need points i’m sorry but yea lol good luck
Answer:
732.9 mmHg
Explanation:
At the eudiometer tube is the mixture of water and hydrogen gas (H₂), by Dalton's law of the partial pressure, the total pressure of a gas mixture (barometric pressure) is equal to the sum of the partial pressures of the components of the mixture:
Ptotal = Pwater + Phydrogen
752.3 = 19.4 + Phydrogen
Phydrogen = 752.3 - 19.4
Phydrogen = 732.9 mmHg
