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dimulka [17.4K]
2 years ago
12

What is an example of a physical change involving iron and a chemical change involving iron?

Chemistry
2 answers:
Vikentia [17]2 years ago
6 0
Chemical change: is any change the results formation of new chemical substances Physical changes: rearranged molecules but affect internal structures
Sunny_sXe [5.5K]2 years ago
6 0
The chemical change of iron would be iron rusting because it a chemical change. Explain it ahah i gotcha its chemical because iron will react to oxygen and for rust which is a new substance.
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Describe the sunlight and length of day at the start of winter *NO GO OG LE* will give brainliest
natta225 [31]

Answer:

Although the daytime length at the Equator remains 12 hours in all seasons, the duration at all other latitudes varies with the seasons. During the winter, daytime lasts shorter than 12 hours; during the summer, it lasts longer than 12 hours.

Explanation:

Maybe this answer is hopeful in your homework.

7 0
2 years ago
Physical or chemical change? what gave you the idea that it was such? ​
Nana76 [90]

Answer:

Chemical Change

Explanation:

It changes color and produces vapor when the foil is added to the solution.

3 0
3 years ago
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A sample of oxygen has a volume of 7.84 mL at a pressure of 71.8 mmHg and a
Andru [333]

here is an attached photo with a detailed explanation, good luck!

4 0
2 years ago
How many grams of a stock solution that is 92.5 percent H2SO4 by mass would be needed to make 250 grams of a 35.0 percent by mas
IrinaVladis [17]

94.6 g.  You must use 94.6 g of 92.5 % H_2SO_4 to make 250 g of 35.0 % H_2SO_4.

We can use a version of the <em>dilution formula</em>

<em>m</em>_1<em>C</em>_1 = <em>m</em>_2<em>C</em>_2

where

<em>m</em> represents the mass and

<em>C</em> represents the percent concentrations

We can rearrange the formula to get

<em>m</em>_2= <em>m</em>_1 × (<em>C</em>_1/<em>C</em>_2)

<em>m</em>_1 = 250 g; <em>C</em>_1 = 35.0 %

<em>m</em>_2 = ?; _____<em>C</em>_2 = 92.5 %

∴ <em>m</em>_2 = 250 g × (35.0 %/92.5 %) = 94.6 g

4 0
3 years ago
I need help solving this!
zmey [24]

Answer: Moles of hydrogen required are 4.57 moles to make 146.6 grams of methane, CH_{4}.

Explanation:

Given: Mass of methane = 146.6 g

As moles is the mass of a substance divided by its molar mass. So, moles of methane (molar mass = 16.04 g/mol) are calculated as follows.

Moles = \frac{mass}{molar mass}\\= \frac{146.6 g}{16.04 g/mol}\\= 9.14 mol

The given reaction equation is as follows.

C + 2H_{2} \rightarrow CH_{4}

This shows that 2 moles of hydrogen gives 1 mole of methane. Hence, moles of hydrogen required to form 9.14 moles of methane is as follows.

Moles of H_{2} = \frac{9.14}{2}\\= 4.57 mol

Thus, we can conclude that moles of hydrogen required are 4.57 moles to make 146.6 grams of methane, CH_{4}.

5 0
3 years ago
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