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Angelina_Jolie [31]

3 years ago

8

What happens to the motion of an object when the forces acting on it are balanced? A. The motion changes. B. The motion does not

change. C.The motion speeds up. D. The motion slows down.

1 answer:

AlexFokin [52]3 years ago

5 0

The answer is B the mation does not change..?? did i get ir right.

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An object accelerates from rest at a constant rate covering a distance of 18 meters in 3 seconds. What is its rate of accelerati

ozzi

Answer:

4

18*2=36
36/(3*3)=4

4 0

3 years ago

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During a test crash and airbag in place to stop at dummies forward motion the dummies mass is 75 kg if the net force of the dumm

strojnjashka [21]

The dummy's acceleration is 11 m/s^2
(also known as 11 meters per sec. per sec.)

a = F/m
= 825 N/75 kg
= 11 m/s^2

3 0

3 years ago

forces of 3.0 N (west) and 4.0 N (33° S of E) act on an object. What is the net force of the object? Calculate both magnitude an

alexandr402 [8]

The net force is 2.2 N at 80.9 degrees south of east

Explanation:

In order to find the net force, we have to resolve each force along the x-y direction, and then add the components in each direction.

Taking east as positive x-direction and north as positive y-direction, we have:

- First force:

$F_{1x} = -3.0 N\\F_{1y} = 0$

- Second force:

$F_{2x} = (4.0)(cos (-33^{\circ})=3.35 N\\F_{2y} = (4.0)(sin (-33^{\circ})=-2.18 N$

Therefore, the components of the net force are

$F_x = F_{1x}+F_{2x}=-3.0+3.35=+0.35 N\\F_y = F_{1y}+F_{2y}=0+(-2.18)=-2.18 N$

And so, the magnitude of the net force is

$F=\sqrt{F_x^2+F_y^2}=\sqrt{(0.35)^2+(-2.18)^2}=2.2 N$

And the direction is

$\theta=tan^{-1}(\frac{F_y}{F_x})=tan^{-1}(\frac{-2.18}{0.35})=-80.9^{\circ}$

which means 80.9 degrees south of east.

Learn more about vector addition:

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6 0

3 years ago

If we shake the branches of tree, the fruits fall why<br>

Leno4ka [110]

The motion of the branch being shaken causes the fruit to detach off the branch, and gravity helps make the fruit fall.

7 0

3 years ago

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An elastic conducting material is stretched into a circular loop of 10.7 cm radius. It is placed with its plane perpendicular to

valina [46]

Answer:

0.44 V

Explanation:

Parameters given:

Radius of loop, r = 10.7 cm = 0.107 m

Magnetic field strength, B = 0.803 T

Rate of shrinkage of Radius, dr/dt = 81 cm/s = 0.81m/s

EMF induced is given in terms of magnetic Flux, Φ, as:

EMF = dΦ/dt

Magnetic Flux, Φ, is given as:

Φ = B * A (where A is area of loop)

Therefore, EMF is:

EMF = d(B*A)/dt

The area of the loop is given as A = πr²

EMF = d(Bπr²) / dt = Bπ*d(r²)/dt

=> EMF = Bπ*2r*(dr/dt)

EMF = 0.803 * π * 2 * 0.107 * 0.81

EMF = 0.44 V

3 0

4 years ago