What is the amount of heat absorbed when the temperature of 75 grams of water increases from 20.°C to 35°C
2 answers:
Answer:
<u><em>4.704625 kJ (or 4704.625 J) </em></u> is the amount of heat absorbed when the temperature of 75 grams of water increases from 20.°C to 35°C.
Explanation:
The measurement and calculation of the amounts of heat exchanged by a body or system is called calorimetry.
In this way, there is a direct proportionality relationship between heat and temperature. The constant of proportionality depends on the substance that constitutes the body as its mass, and the product of specific heat is produced by the body's mass. So, the equation that allows to calculate heat exchanges is:
Q = c * m * T
Where Q is the heat exchanged for a body of mass m, constituted by a specific heat substance c and where T is the temperature variation.
In this case:
- The specific heat capacity (c) of water is 4,181 J / g°C
- m=75 g
- T=35°C - 20°C ⇒ T= 15°C
Then:
Q≅4704.625 J
Being 1 kJ = 1000 J:
Q=4.704625 kJ
Finally, <u><em>4.704625 kJ (or 4704.625 J) is the amount of heat absorbed when the temperature of 75 grams of water increases from 20.°C to 35°C</em></u>
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Answer:
a. minimum voltage that must be supplied for a redox reaction to occur
c. always equal to Eanode - Ecathode
Explanation:
In an electrolytic cell; The electromotive force(the maximum standard potential difference) of the cell formed by the system is defined as the standard electrode potential of the right handed electrode minus the standard electrode potential of the left hand electrode. (i.e )
As we all known that the process by which chemical energy is being converted to electrical energy is called the Electrochemical cell. It consists of two half cells , an oxidation half cell reaction and a reduction half-cell reaction.The overall redox reaction results in a flow of electrons in an electric current which is produced by a minimum voltage.
Therefore, option a and c are both correct.