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Leno4ka [110]
4 years ago
11

A beta particle is a(n):

Physics
1 answer:
nirvana33 [79]4 years ago
6 0

Answer:

Electron emitted by nucleus.

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Estimate the number of times the earth will rotate on its axis during a human’s lifetime
Fudgin [204]

Here we have to calculate  the number of rotations made by earth around its own axis in the entire life time of a human being.

The average human life is 50 years .

Each year is 365.5 days

Hence 50 years =50 *365.5 days

                 =18,275 days

The earth rotates around its own axis in 23 hours 56 minutes and 4 second which is approximately equal to 24 hours or one days.

Hence one rotation takes one days.

⇒18,275 days =18,275 rotations

Hence the total number of rotations made by earth around its own axis in the life time of a average human life time will be 18,275 times

7 0
3 years ago
Mike is a runner. Mike runs 200m in 25s; what is his average velocity during the run? assume that units are in m/s. (asap, will
maw [93]
Velocity is displacement/time
(Displacement is the overall change in distance)

So you’ll want to divide 200 by 25, which should give you:

8 m/s

5 0
3 years ago
Estimated speed of the vehicle
SSSSS [86.1K]

Really, Gundy ? ! ?

The formula for the car's speed is given and discussed in the box.  The formula is

v = √(2·g·μ·d)

Then they <em>tell</em> you that μ is 0.750 , and then they <em>tell</em> you that d = 52.9 m .  Also, everybody knows that 'g' is gravity = 9.8 m/s² .

They also tell us that the mass of the car is 1,000 kg, and they tell us that it took 3.8 seconds to skid to a stop.  But we already <em>have</em> all the numbers in the formula <em>without</em> knowing the car's mass or how long it took to stop.  The police don't need to weigh the car, and nobody was there to measure how long the car took to stop.  All they need is the length of the skid mark, which they can measure, and they'll know how fast the guy was going when he hit the brakes !

Now, can you take the numbers and plug them into the formula ? ! ?

v = √(2·g·μ·d)

v = √( 2 · 9.8 m/s² · 0.75 · 52.9 m)

v = √( 777.63 m²/s²)

v = 27.886 m/s

Rounded to 3 digits, that's  <em>27.9 m/s </em>.

That's about 62.4 mile/hour .



3 0
4 years ago
A weather balloon is Floating at a constant height above Earth when it releases a pack hot instruments. If the pack hits the gro
Slav-nsk [51]

Answer:

The pack has fallen 275.6 m

Explanation:

The pack is in free fall, so it is moving by uniform accelerated motion, so we can use the following suvat equation:

v^2-u^2=2as

where, choosing upward as positive direction:

v is the final velocity

u is the initial velocity

a=g=-9.8 m/s^2 is the acceleration of gravity

s is the vertical displacement

For the pack in this problem,

u = 0

v = -73.5 m/s

Solving for s, we find how far the packet has fallen:

s=\frac{v^2-u^2}{2a}=\frac{(-73.5)^2-0^2}{2(-9.8)}=-275.6 m

And the negative sign means the direction of the displacement is downward.

5 0
3 years ago
Review. One electron collides elastically with a second electron initially at rest. After the collision, the radii of their traj
DochEvi [55]

The energy of the incident electron in keV is 5.51× 10—²² keV.

Capacity or ability to do work is termed energy. Energy exists in various forms. It can be in the form of mechanical, potential, thermal, kinetic, and many other forms. Joules is the SI of the energy. The potential energy of a system is defined as the energy stored due to its position. While kinetic energy is defined as the energy

stored due to its position.

Radius1 of the trajectory = 1.00 cm

Radius2 of the trajectory = 2.4 0 cm

The magnitude of the uniform magnetic field = 0.0440 T

A Uniform magnetic field is perpendicular to the trajectories.

The velocity of the incident electron is,

v =  \frac{eBR}{m}

The energy of the incident electron is,

K =  \frac{1}{2} mv ^{2}

K =  \frac{1}{2} \frac{(eBR)}{m}^{2}

The energy in keV is,

1-kilo electron volt = 1000 electron volts

1 keV = 1000 eV

1 \: eV =  \frac{1}{1000} \:  keV

= \frac{ K}{1000}

=  \frac{eB ^{2} R ^{2} }{2000m}

= 5.51 \times 10 ^{ - 22}  \: keV

Therefore, the energy of the incident electron in keV is 5.51× 10—²² keV.

To know more about electrons, refer to the below link:

brainly.com/question/1255220

#SPJ4

6 0
1 year ago
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