A 50g ice cube at 0 degrees celcius is added to a glass containing 400g of water at 45 degrees celcius. What is the final temper
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Answer:
Hi, the question is incomplete. However, the question is about the calculation of volume of a product when the volume of one of the reactants is provided.
9.587 cm^3
Explanation:
The balanced equation for the chemical reaction is shown below:
⇒
In the chemical reaction above, 2 moles of water produced 4 moles of hydrogen fluoride. If 4.8 cm^3 of water were consumed, we can calculated the volume of hydrogen fluoride that would be produced as follow:
Using STP, 1 mole of gas has a volume of 22.4 L
Thus, 4.8 cm^3 = 0.0048 L is equivalent to 2.14*10^-4
since 2 moles of water produced 4 moles of hydrogen fluoride, therefore, 2.14*10^-4 would produced 2*2.14*10^-4 = 4.28*10^-4 moles
we can convert the moles to L by multiplying with 22.4
volume of hydrogen fluoride = 4.28*10^-4 * 22.4 = 0.009587 L = 9.587 cm^3
Explanation:
The given data is as follows.
Mass of refrigerant, m = 10 kg
Volume of the refrigerant, V = 1.595
Formula for specific volume of the refrigerant is as follows.
v =
= 0.1595
So, at specific volume will be within
and
and pressure is constant.
The fluid will be in super-heated state at temperature and at T =
pressure 1 bar = 0.1 MPa.
According to super-heated tables, the specific volume is v = 0.30138 .
Hence, the final volume will be calculated as follows.
=
= 3.0138
Thus, we can conclude that final volume of the R-134a is 3.0138 .