Question

Please explain how to solve this!! What is the power dissipated by a toaster that has a resistance of 60 ohms and is plugged into a 120-V outlet? Show your work.

Answer 1

Answer: The correct answer is 240 W.

Explanation:

The expression for the power in terms of resistance and potential is as follows;

$P=\frac{V^{2} }{R}$

Here, V is the potential, P is the power and R is the resistance.

It is given in the problem that the toaster has a resistance of 60 ohms and is plugged into a 120-V outlet

Calculate the power dissipation.

$P=\frac{V^{2} }{R}$

Put V= 120 V and R= 60 ohms.

$P=\frac{120^{2} }{60}$

Therefore, the value of the power dissipation is 240 W.

Answer 2

The power dissipated is simply V^2/R

where V = 120 volts RMS
and R = 60 Ω