Answer:
So the car would skid 4 times the initial skidding displacement under the identical conditions when the car's initial velocity is just double.
Explanation:
Under identical conditions when the brakes are applied for the same body moving with twice the initial speed then we can analyse using the equation of motion.
Initially:
...........................(1)
where:
final velocity of the car = 0 (because the car stops)
initial velocity of the car
acceleration of the car (here it is deceleration and hence taken with negative sign)
displacement of the car before stopping
Final condition:
Initial velocity is,
So,
.............................(2)
Now divide eq. (2) by (1)
So the car would skid 4 times the initial skidding displacement under the identical conditions when the car's initial velocity is just double.
If you kick the ball and that's the action force, then wouldn't the reaction force be the ball moving in the direction you kicked it?
Answer:
The velocity of the center of mass of the two-ball system is 13.1 m/s.
Explanation:
Given;
mass of the first ball, m₁ = 0.5 kg
mass of the second ball, m₂ = 0.25 kg
initial velocity of the second ball, u₂ = 19.6 m/s
At the highest point the velocity of the second ball, v₂ = 0
The highest point reached by the second ball is calculated as;
v₂² = u₂² - 2gh
0 = u₂² - 2gh
2gh = u₂²
h = u₂² / 2g
h = (19.6²) / (2 x 9.8)
h = 19.6 m
The final velocity of the first ball when it had traveled 19.6 m down;
v₁² = u₁² + 2gh
v₁² = 0 + 2gh
v₁ = √2gh
v₁ = √(2 x 9.8 x 19.6)
v₁ = 19.6 m/s
The velocity of the center of mass of the two-ball system is calculated as;
Answer:
The resistor to be hooked up must be 9900
Explanation:
Recall how resistors in parallel combine to render an equivalent resistor:
So we need to find which resistor (R2) we need to combine in parallel with resistor R1 (100 ) in order to obtain an equivalent resistor Re (99 ) :