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Mice21 [21]
3 years ago
14

A ball having a mass of 0.20 kilograms is placed at a height of 3.25 meters. If it is dropped from this height, what will be the

kinetic energy of the ball when it reaches 1.5 meters above the ground?
Physics
2 answers:
Julli [10]3 years ago
3 0
Initially the total energy of the object, which is only PE.

PE = mgh = 0.2kg * 10m/s² * 3.25m = 6.5 J

When it is at 1.5m above the ground, it has both Kinetic and Potential Energy.

At 1.5m above the ground:
<span>PE = mgh = 0.2kg * 10m/s² * 1.5m = 3 J
</span>
But at such mid level, PE + KE 

PE + KE = Total (Conserved) 

3 + KE = 6.5

KE = 6.5 - 3 = 3.5

Kinetic energy at 1.5 above ground = 3.5 J
serious [3.7K]3 years ago
3 0
We are given with the mass of the ball and the initial and final height of the ball when dropped from a height. The kinetic energy is obtained by first determining the final velocity of the ball. We use the formula 2ax = v^2 where a is equal to 9.8 m/s2 and x is equal to 3.25-1.5 or 1.75 meters. velocity is equal to 5.86 m/s. kinetic energy is mv2 where m is 0.20 kg. the answer is 6.87 Joules. 
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sineoko [7]
W = mg = 350 newton
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on mars
W = mg = 134 newton
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They are said to be directly related.

a) directly related.

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Choice A.

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6 0
3 years ago
Each of the following diagrams shows a spaceship somewhere along the way between Earth and the Moon (not to scale); the midpoint
djyliett [7]

Answer:

F_5 >F_4>F_1 >F_2>F_3

Where F_i represent the force for each of the 5 cases i -1,2,3,4,5 presented on the figure attached.

Explanation:

For this case the figure attached shows the illustration for the problem

We have an inverse square law with distance for the force, so then the force of gravity between Earth and the spaceship is lower when the spaceship is far away from Earth.

Th formula is given by:

F = G \frac{m_{Earth} m_{Spaceship}}{r^2}

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For this reason when the distance between the Earth and the Spaceship increases the Force of gravity needs to decrease since are inversely proportional the force and the radius, and for the other case when the Earth and the spaceship are near then the radius decrease and the Force increase.

Based on this case we can create the following rank:

F_5 >F_4>F_1 >F_2>F_3

Where F_i represent the force for each of the 5 cases i -1,2,3,4,5 presented on the figure attached.

6 0
3 years ago
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