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FromTheMoon [43]
3 years ago
10

To receive a different radio channel, you must change the

Physics
2 answers:
NikAS [45]3 years ago
8 0
<span>To receive a different radio channel, you must change the </span>A. wave frequency being received
forsale [732]3 years ago
6 0
I Believe the answer Is A wave frequency Being recieved


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If the period of the pendulum is tripled, what is the length of the string increased by?
Nitella [24]
The period of the pendulum doesn't determine the length of the string. 
It's the other way around.

The period of the pendulum is proportional to the square root of its length.
So if you want to triple the period, you have to make the string nine times
as long as it is now.
7 0
3 years ago
If 2.40 g of KNO3 reacts with sufficient sulfur (S8) and carbon (C), how much P-V work will the gases do against an external pre
creativ13 [48]

Answer:

-112.876J

Explanation:

In order to solve this question, we would need to incorporate Stoichiometry, which involves using relationships between reactants and/or products in a chemical reaction to determine desired quantitative data.

Here's a balanced equation for the reaction:

16KNO_3(s) + 24C(s) + S_8(s)    \to 24CO_2(g) + 8N_2(g) + 8K_2S(s)

Let us define P - V work as;

w_{pv} = - P_{external}  \triangle Volume

where  \triangle (Volume) = (V_{final} - V_{initial})

External pressure is given as  1.00atm , therefore the work solely depends on the change in volume and since the reactants are solids, none of the reactants contribute to the volume. Hence,  V_i = 0.

To find the volume of the products, we need to first find the amount of moles of the product made from  2.40_gKNO_3, using the molar mass of  KNO_3  which is 101.1032 g/mol  

2.40_gKNO_3 . {\frac{1molKNO_3}{101.1032_g}} = 0.0237molKNO_3

Now let us convert moles of  KNO_3  into moles of CO_2 and N_2  using the stoichiometric ratios from our balanced equation of the reaction.

0.0237molKNO_3 . {\frac{24molCO_2}{16molKNO_3}} = 0.0356molCO_2

0.0237molKNO_3 . {\frac{8molN_2}{16molKNO_3}} = 0.01185molN_2

K_2S is not factored into the volume calculation because it is a solid.

Now let us also convert the moles of  CO_2  and  N_2 into grams using their respective molar masses.

0.0356molCO_2 . {\frac{44.01_g}{1molCO_2}} = 1.567_gCO_2

0.01185molN_2 . {\frac{28.014_g}{1molN_2}} = 0.332_gN_2

We will now proceed to convert grams into volume using the density values provided.

1.567_gCO_2 . {\frac{1L}{1.830_g}} = 0.856LCO_2

0.332_gN_2 . {\frac{1L}{1.165_g}} = 0.285LN_2

Summing up the two volumes, we get the final volume

0.856L + 0.258L = 1.114L = V_f

Plugging everything into the w_{pv} equation, we get:

w_{pv} = -1atm(1.114L - 0L) = -1.114L.atm

Finally, let us convert L.atm into joules using the conversion rate of;

1L.atm = 101.325J\\-1.114L.atm. {\frac{101.325J}{1L.atm}} = -112.876J

7 0
3 years ago
All objects at any temperature emit radiant energy true or false
kirill [66]
The answer is true.
All object at any temperature emit radiant energy.
4 0
3 years ago
Read 2 more answers
What is a vector quantity?<br><br>​
Nat2105 [25]

Answer:

A quantity that has magnitude and direction. It's usually represented by an arrow whose direction is the same direction is the same as that of the quantity and whose length is proportional to the quantity's magnitude

7 0
2 years ago
A ruby laser delivers a 16.0-ns pulse of 4.20-MW average power. If the photons have a wavelength of 694.3 nm, how many are conta
stepan [7]

Answer:

The  value is  n  =  2.347 *10^{17} \  photons

Explanation:

From the question we are told that

     The  amount of power delivered is  P  =  4.20 \  M W  =  4.20  *10^{6} \  W

      The  time taken is  t =  16.0ns  =  16.0 *10^{-9} \  s

       The  wavelength is  \lambda  =  694.3 \  nm =  694.3 *10^{-9} \  m

     

Generally the energy delivered is  mathematically represented as

     E  =  P  * t  =  \frac{n  *  h  *  c  }{\lambda }

Where  h is the Planck's constant with value  h  =  6.262  *10^{-34} \  J \cdot  s

           c  is the speed of light with value  c =  3.0*10^{8} \  m/s

     

So  

    4.20 *10^{6}  *  16*10^{-9}=  \frac{n  *  6.626 *10^{-34}  *  3.0*10^{8}  }{694.3 *10^{-9}}

=>    n  =  2.347 *10^{17} \  photons

4 0
3 years ago
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