Micah knows that a car had a change in velocity of 15 m/s.To determine acceleration ,Micah also needs the blank of the total tri
2 answers:
Answer: To determine acceleration ,Micah also needs the Time of the total trip in seconds.
Explanation:
Acceleration can be defined as rate of change of velocity.
for calculating acceleration, initial and final velocity are required in meter per second and the total time of the trip in seconds. Then acceleration is measured in meter per second square.
Thus, Micah knows that a car had a change in velocity of 15 m/s.To determine acceleration ,Micah also needs the <u>Time</u> of the total trip in seconds.
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Answer:
The tensions in is approximately 4,934.2 lb and the tension in
is approximately 6,035.7 lb
Explanation:
The given information are;
The angle formed by the two rope segments are;
The angle, Φ, formed by rope segment BC with the line AB extended to the center (midpoint) of the ship = 26.0°
The angle, θ, formed by rope segment BD with the line AB extended to the center (midpoint) of the ship = 21.0°
Therefore, we have;
The tension in rope segment BC =
The tension in rope segment BD =
The tension in rope segment AB = = Pulling force of tugboat = 1200 lb
By resolution of forces acting along the line A_F gives;
× cos(26.0°) +
× cos(21.0°) =
= 1200 lb
× cos(26.0°) +
× cos(21.0°) = 1200 lb............(1)
Similarly, we have for equilibrium, the sum of the forces acting perpendicular to tow cable = 0, therefore, we have;
× sin(26.0°) +
× sin(21.0°) = 0...........................(2)
Which gives;
× sin(26.0°) = -
× sin(21.0°)
= -
× sin(21.0°)/(sin(26.0°)) ≈ -
× 0.8175
Substituting the value of, , in equation (1), gives;
- × 0.8175 × cos(26.0°) +
× cos(21.0°) = 1200 lb
- × 0.7348 +
×0.9336 = 1200 lb
×0.1988 = 1200 lb
≈ 1200 lb/0.1988 = 6,035.6938 lb
≈ 6,035.6938 lb
≈ -
× 0.8175 = 6,035.6938 × 0.8175 = -4934.1733 lb
≈ -4934.1733 lb
From which we have;
The tensions in ≈ -4934.2 lb and
≈ 6,035.7 lb.