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san4es73 [151]
3 years ago
14

How far did a car travel if it was on the road for 55.2s and it traveled at an average speed of 55m/s

Physics
1 answer:
pantera1 [17]3 years ago
3 0
The car traveled 1.00363 kilometers in the 55.2s and the speed of 55m/s
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3 years ago
The wheels of a car have radius 12 in. and are rotating at 600 rpm. Find the speed of the car in mi/h.
guajiro [1.7K]

Answer:

21.4 mph

Explanation:

Circumference of tire in FEET   = pi * d =  pi * 1 ft = pi  feet

pi feet  x  600 rot/min  *  60 min /hr  *  1 mile / 5280 feet = 21.4 mph

7 0
11 months ago
A 2800 kg truck moving at 12 m/s to the right hits a stopped 1100 kg car. What is the combined velocity the moment they stick to
leva [86]

Answer:

The combined velocity is 8.61 m/s.

Explanation:

Given that,

The mass of a truck, m = 2800 kg

Initial speed of truck, u = 12 m/s

The mass of a car, m' = 1100 kg

Initial speed of the car, u' = 0

We need to find the combined velocity the moment they stick together. Let it is V. Using the conservation of momentum.

m_1v_1+m_2v_2=(m_1+m_2)V\\\\V=\dfrac{m_1v_1+m_2v_2}{(m_1+m_2)}\\\\V=\dfrac{2800\times 12+0}{2800+1100}\\\\V=8.61\ m/s

So, the combined velocity is 8.61 m/s.

5 0
2 years ago
Find focal length of a concave mirror having 40 cm radius of curvature​
nignag [31]

Answer:

The focal length of the given spherical mirror is 20cm.

Explanation:

plz follow me

5 0
3 years ago
A toy train is pushed forward and released at Xi = 4.0 m with a speed of 2.5 m/s. It rolls at a steady speed for 2.0 s, then one
Fittoniya [83]
I don't think that 4m has anything to do with the problem. anyway. here. A___________________B_______C where A is the point that the train was released. B is where the wheel started to stick C is where it stopped From A to B, v=2.5m/s, it takes 2s to go A to B so t=2 AB= v*t = 2.5 * 2 = 5m The train comes to a stop 7.7 m from the point at which it was released so AC=7.7m then BC= AC-AB = 7.7-5 = 2.7m now consider BC v^2=u^2+2as where u is initial speed, in this case is 2.5m/s v is final speed, train stop at C so final speed=0, so v=0 a is acceleration s is displacement, which is BC=2.7m substitute all the number into equation, we have 0^2 = 2.5^2 + 2*a*2.7 0 = 6.25 + 5.4a a = -6.25/5.4 = -1.157 so acceleration is -1.157m/(s^2)
8 0
3 years ago
Read 2 more answers
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