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3 years ago

Help???? I don't understand conversion factors

Chemistry

1 answer:

lisov135 [29]3 years ago

4 0

1. There are 41.99 grams in 4.5 moles of sodium fluoride.

2. There are 1.26 moles in 98.3 grams of aluminum hydroxide.

3. There are 5 grams in 0.02 moles of beryllium iodide.

4. There are 0.70 moles in 68 grams of copper (II) hydroxide.

5. There are 0.064 grams in 2.3x10^-4 moles of calcium phosphate.

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Why is the collision theory considered to be well-established and highly reliable?

hodyreva [135]

BECAUSE IT NEVER BREAKES

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4 years ago

Temperature is a measure of _____.

Rzqust [24]

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Hope this helps. :)

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4 years ago

A reaction of importance in the formation of smog is that between ozone and nitrogen monoxide described by O 3 ( g ) + NO ( g )

Aleksandr [31]

Answer:

(a) 7.11x10⁻⁴ M/s

(b) 2.56 mol.L⁻¹.h⁻¹

Explanation:

(a) The reaction is:

O₃(g) + NO(g) → O₂(g) + NO₂(g) (1)

The reaction rate of equation (1) is given by:

$rate = k*[O_{3}][NO]$ (2)

k: is the rate constant of reaction = 3.91x10⁶ M⁻¹.s⁻¹

[O₃]₀ = 2.35x10⁻⁶ M

[NO]₀ = 7.74x10⁻⁵ M

Hence, to find the inital reacion rate we will use equation (2):

$rate = k*[O_{3}]_{0}[NO]_{0} = 3.91 \cdot 10^{6} M^{-1}s^{-1}*2.35\cdot 10^{-6} M*7.74 \cdot 10^{-5} M = 7.11 \cdot 10^{-4} M/s$

Therefore, the inital reaction rate is 7.11x10⁻⁴ M/s

(b) The number of moles of NO₂(g) produced per hour per liter of air is:

t = 1 h

V = 1 L

$\frac{\Delta[NO_{2}]}{\Delta t} = rate$

$\frac{\Delta[NO_{2}]}{\Delta t} = 7.11 \cdot 10^{-4} M/s*\frac{3600 s}{1 h} = 2.56 mol.L^{-1}.h{-1}$

Hence, the number of moles of NO₂(g) produced per hour per liter of air is 2.56 mol.L⁻¹.h⁻¹

I hope it helps you!

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3 years ago

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1/16 ( ignore this the stupid website just makes us use 20 characters UGH! )

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3 years ago

H2S what species are present at 10-6 mol/L or greater when dissolved in water

Anastaziya [24]

Answer:

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Explanation:

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3 years ago