Answer: Simpe its 1
Explanation:I took that quiz before hope this helps :)
Answer:
ΔG° = 1747.523
Explanation:
The parameters mentioned are;
Gibbs Free energy ΔG°
Equilibrium constant Kc
Temperature T = 37 + 273 = 310 (upon conversion to kelvin temperature)
The formular relating all three parameters is given as;
ΔG° = -RTlnKc
Where; R = rate constant = 8.314 J⋅K−1⋅mol−1
Upon solving;
ΔG° = - 8.314 * 310 * ln(1.97)
ΔG° = 1747.523
1, it has the same number of Carbon, Hydrogen, and Oxygen atoms
This question is too complex but ill answer it since its ez :/
1. Sulfur ion
2. Ga^+3
3. OH⁻ : hydroxide, PO₄⁻³ : phosphate
4. <span>Common names do not provide information about the chemical composition of the compound
5. potassium</span>
Answer:
Percentage yield = 57.57%
Explanation:
Given data:
Actual yield of carbondioxide = 38.0 g
Mass of propane = 22.05 g
Percentage yield = ?
Solution:
Chemical equation:
C₃H₈ + 5O₂ → 3CO₂ + 4H₂O
Number of moles of propane:
Number of moles of propane = mass / molar mass
Number of moles of propane = 22.05 g/ 44 g/mol
Number of moles of propane = 0.5 mol
Now we compare the moles of carbon dioxide with moles of propane.
C₃H₈ : CO₂
1 : 3
0.5 : 3×0.5 = 1.5 mol
Mass of carbondioxide:
Mass of carbondioxide = moles × molar mass
Mass of carbondioxide = 1.5 mol × 44 g/mol
Mass of carbondioxide = 66 g
Percentage yield:
Percentage yield = actual yield / theoretical yield × 100
Percentage yield = 38 g/ 66 g × 100
Percentage yield = 57.57%