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kati45 [8]
3 years ago
12

The following diagram shows various positions of the moon in its orbit around Earth. The image of the moon shows its phase as se

en from Earth.
In which position will three-fourths of the illuminated side of the moon be visible from Earth?

A) A
B) B
C) C
D) D

Physics
2 answers:
inysia [295]3 years ago
3 0
<span>Three-fourths of the illuminated side of the moon be visible
from Earth when the moon is at position-B.  (choice-B)


Notice the particularly egregious screw-up on the drawing at the
"Third Quarter" position.  There, the drawing shows the illuminated 
side of the moon AWAY from the sun, and the dark side of the moon
TOWARD the sun.  That's about as silly as you can get.  </span>
kykrilka [37]3 years ago
3 0

Answer:

B) B      

Explanation:

As the moon revolves about the Earth, we see different shapes of the moon everyday.  Phases of moon occur as different portion of illuminated side of the moon is visible from the earth.

According to diagram, at position A, there is full moon phase.

At position C, the illuminated side does not face the earth, so new phase occurs.

At position D, the moon is moving from new moon phase to half moon, so it will be crescent phase.

At position B, the moon is moving from full moon to half moon phase. So at B, it will be in gibbous phase - three-fourths of the illuminated side of the moon would be visible.

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AveGali [126]

The best and most correct answer among the choices provided by your question is the fourth option or letter D. Trade winds blow towards the equator because t<span>he Equator receives the most heat energy.

</span>The surface air that flows from these subtropical high-pressure belts toward the Equator is deflected toward the west in both hemispheres by the Coriolis effect. These winds blow<span> predominantly from the northeast in the Northern Hemisphere and from the southeast in the Southern Hemisphere.

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3 0
3 years ago
A 350-N child is in a swing that is attached to a pair of ropes 2.10 m long. Find the gravitational potential energy of the chil
o-na [289]

Answer:

a)  U = 735 J , b) U = 125.7 J , c)   U = 0 J

Explanation:

The gravitational power energy is

      U = mg y - mg y₀

The last value is a constant, for simplicity we can make it zero, if the lowest point is at the origin of the coordinate system, which in this case we will place in the lowest part

a) Rope is horizontal

The height in this case is the same length of the rope

     y = 2.10 m

    w = mg = 350 N

    U = 350 2.10

    U = 735 J

b) when the angle is 34º

     y = L - L cos 34

    y = L (1- cos34)

    y = 2.10 (1- cos 34)

    y = 0.359 m

    U = 350 0.359

    U = 125.7 J

c) in this case this point coincides with the reference system

     y = 0

     U = 0 J

4 0
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Which of these has the greatest influence over how big a baby elephant will grow?
lina2011 [118]
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An ordinary flashlight battery has a potential difference of 1.2 V between its positive and negative terminals. How much work mu
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The work done to transport an electron from the positive to the negative terminal is 1.92×10⁻¹⁹ J.

Given:

Potential difference, V = 1.2 V

Charge on an electron, e = 1.6 × 10⁻¹⁹ C

Calculation:

We know that the work done to transport an electron from the positive to the negative terminal is given as:

W.D = (Charge on electron)×(Potential difference)

       = e × V

       = (1.6 × 10⁻¹⁹ C)×(1.2 V)

       = 1.92 × 10⁻¹⁹ J

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