1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
kati45 [8]
3 years ago
12

The following diagram shows various positions of the moon in its orbit around Earth. The image of the moon shows its phase as se

en from Earth.
In which position will three-fourths of the illuminated side of the moon be visible from Earth?

A) A
B) B
C) C
D) D

Physics
2 answers:
inysia [295]3 years ago
3 0
<span>Three-fourths of the illuminated side of the moon be visible
from Earth when the moon is at position-B.  (choice-B)


Notice the particularly egregious screw-up on the drawing at the
"Third Quarter" position.  There, the drawing shows the illuminated 
side of the moon AWAY from the sun, and the dark side of the moon
TOWARD the sun.  That's about as silly as you can get.  </span>
kykrilka [37]3 years ago
3 0

Answer:

B) B      

Explanation:

As the moon revolves about the Earth, we see different shapes of the moon everyday.  Phases of moon occur as different portion of illuminated side of the moon is visible from the earth.

According to diagram, at position A, there is full moon phase.

At position C, the illuminated side does not face the earth, so new phase occurs.

At position D, the moon is moving from new moon phase to half moon, so it will be crescent phase.

At position B, the moon is moving from full moon to half moon phase. So at B, it will be in gibbous phase - three-fourths of the illuminated side of the moon would be visible.

You might be interested in
On the moon, the acceleration due to gravity is one-sixth that of earth. That is gmoon = gearth /6 = (9.8 m/s2 )/6 = 1.63 m/s2 .
MAVERICK [17]
The pendulum would differ from 300 inches
8 0
3 years ago
Distance = 6 km south<br><br> 60 minutes<br><br> What was the average velocity
blsea [12.9K]

v = x/t

v = average velocity, x = displacement, t = elapsed time

Given values:

x = 6km south, t = 60min

Plug in and solve for v:

v = 6/60

v = 0.1km/min south

3 0
3 years ago
Read 2 more answers
In a shipping yard, a crane operator attaches a cable to a 1,400 kg shipping container and then uses the crane to lift the conta
Molodets [167]

Answer:

Explanation:

Given

mass of crane m=1400\ kg

distance moved d=40\ m

Since it is moving with a constant velocity therefore net force on it is zero

Tension force=weight

T=mg

Work done by Tension T is

W_T=T\cdot d

W_T=1400\times 9.8\cdot 40

W_T=548.8\ KJ

Work done by Gravity will be equal in magnitude but opposite in sign and can be obtained by work energy theorem which states that change in kinetic energy of object is equal to work done by all the forces

W_T+W_g=0

W_g=-548.8\ KJ

                                 

4 0
3 years ago
A 1560-kilogram truck moving with a speed of 28.0 m/s runs into the rear end of a 1070-kilogram stationary car. If the collision
Nimfa-mama [501]

Answer:

Δ KE =  249158.6 kJ  

Explanation:

given data

Truck mass  M =  1560 Kg

Truck initial speed, u = 28 m/s

mass of car m = 1070 Kg

initial speed of car u1 = 0 m/s

solution

first we get here final speed by using conservation of momentum  that is express as

Mu = (M+m) V     .......................1

put here  value we get

1560 × 28 = (1560 + 1070 ) V

solve it we get

final speed V = 16.60 m/s

and

Change in kinetic energy  will be here

Δ KE =   \frac{1}{2} Mu^2 - \frac{1}{2}(M+m)V^2         .................2

put here value and we get

 Δ KE = \frac{1}{2}\times 1560\times 28^2 - \frac{1}{2}\times (1560 + 1070)\times 16.60^2  

solve it we get

Δ KE =  249158.6 kJ  

6 0
3 years ago
A ball is thrown vertically upwards from the edge of the cliff and hits the ground at the base of the cliff with a speed of 30 m
olya-2409 [2.1K]

To solve this problem we will apply the linear motion kinematic equations. From the definition of the final velocity, as the sum between the initial velocity and the product between the acceleration (gravity) by time, we will find the final velocity. From the second law of kinematics, we will find the vertical position traveled.

v = v_0 -gt

Here,

v = Final velocity

v_0 = Initial velocity

g = Acceleration due to gravity

t = Time

At t = 4s, v = -30m/s (Downward)

Therefore the initial velocity will be

-30 = v_0 -9.8(4)

v_0 = 9.2m/s

Now the position can be calculated as,

y = h +v_0t -\frac{1}{2}gt^2

When it has the ground, y=0 and the time is t=4s,

0 = h+(9.2)(4)-\frac{1}{2} (9.8)(4)^2

h = 41.6m

Therefore the cliff was initially to 41.6m from the ground

7 0
3 years ago
Other questions:
  • PLEASE HELP ASAP!! WILL MARK AS BRAINLIEST IF ANSWERED NOW!!
    13·1 answer
  • . A chemistry student’s height is measured at 68.5 inches. How tall is the student in cm?
    9·2 answers
  • You and your surfing buddy are waiting to catch a wave a few hundred meters off the beach. The waves are conveniently sinusoidal
    10·2 answers
  • The Temperatureslider controls the heat of the metal filamentinside the light. Scientists use the Kelvin scaleto measure the tem
    9·1 answer
  • A 2.73 kg cylindrical grinding wheel with a radius of 31 cm rotates at 1416 rpm. What is its angular momentum? Answers:
    13·1 answer
  • Which statement describes a property of a proton?
    14·1 answer
  • Un montacargas hidráulico es utilizado para levantar cajas con un peso de 1500 newtons sobre una superficie de 20 cm al cuadrado
    5·1 answer
  • A roller coaster with a potential energy of 235,200 J sits at the top of a 30 m high hill. What is the mass of the roller
    11·2 answers
  • Which statement describes a surface wave?
    8·1 answer
  • 2) Given circuit...V1= 12VR4= 5.00R7= 3.00R2= 4.00R5= 7.00R3= 5.00R6= 3.00R2a) Find the equivalent resistance of the circuit1V1R
    9·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!