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kati45 [8]
3 years ago
12

The following diagram shows various positions of the moon in its orbit around Earth. The image of the moon shows its phase as se

en from Earth.
In which position will three-fourths of the illuminated side of the moon be visible from Earth?

A) A
B) B
C) C
D) D

Physics
2 answers:
inysia [295]3 years ago
3 0
<span>Three-fourths of the illuminated side of the moon be visible
from Earth when the moon is at position-B.  (choice-B)


Notice the particularly egregious screw-up on the drawing at the
"Third Quarter" position.  There, the drawing shows the illuminated 
side of the moon AWAY from the sun, and the dark side of the moon
TOWARD the sun.  That's about as silly as you can get.  </span>
kykrilka [37]3 years ago
3 0

Answer:

B) B      

Explanation:

As the moon revolves about the Earth, we see different shapes of the moon everyday.  Phases of moon occur as different portion of illuminated side of the moon is visible from the earth.

According to diagram, at position A, there is full moon phase.

At position C, the illuminated side does not face the earth, so new phase occurs.

At position D, the moon is moving from new moon phase to half moon, so it will be crescent phase.

At position B, the moon is moving from full moon to half moon phase. So at B, it will be in gibbous phase - three-fourths of the illuminated side of the moon would be visible.

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When hydrogen is fused into helium, energy is released from Choose one: A. the increase in pressure. B. the decrease in the grav
Tatiana [17]

The nuclear fusion of hydrogen atoms releases a huge amount of energy. So the correct choice is C. Conversion of mass to energy.

What is nuclear fusion?

When two small nuclei join to form a new nucleus, then this process is termed nuclear fusion. A huge amount of energy is released when there occurs nuclear fusion between the two nuclei. And a new element is formed.

It has been observed that the amount of energy released in nuclear fusion is equal to the mass difference between the mass of the formed nucleus and the total mass of old nuclei. Hence in the nuclear fusion of hydrogen nuclei to form a helium nucleus, the energy is released due to the conversion of mass into energy.

The pressure is increased to make the hydrogen atoms fuse but this change in pressure does not contribute to the energy released in the fusion of hydrogen.

The magnitude of the gravitational field is too low and it does not contribute to the energy released in the fusion of hydrogen.

The gravitational collapse does not occur between the two hydrogen atoms. This phenomenon occurs in celestial bodies so this also does not contribute to the energy released in the fusion of hydrogen.

Learn more about nuclear fusion here:

brainly.com/question/10165218

#SPJ4

8 0
2 years ago
The y component of the electric field of an electromagnetic wave traveling in the +x direction through vacuum obeys the equation
Alexxx [7]

Answer: 8.6 µm

Explanation:

At a long distance from the source, the components (the electric and magnetic fields) of the electromagnetic waves, behave like plane waves, so the equation for the y component of the electric field obeys an equation like this one:

Ey =Emax cos (kx-ωt)

So, we can write the following equality:

ω= 2.2 1014 rad/sec

The angular frequency and the linear frequency are related as follows:

f = ω/ 2π= 2.2 1014 / 2π (rad/sec) / rad = 0.35 1014 1/sec

In an electromagnetic wave propagating through vacuum, the speed of the wave is just the speed of light, c.

The wavelength, speed and frequency, are related by this equation:

λ = c/f

λ = 3.108 m/s / 0.35. 1014 1/s = 8.6 µm.

7 0
3 years ago
It takes 56.5 kilojoules of energy to raise the temperature of 150 milliliters of water from 5°C to 95°C. If you
natka813 [3]
If 56.5kJ are needed to raise the temp by 90°C and if the heater is 60% efficient that means that:
60% X y = 56.5kJ
where y is the electrical energy in kJ that the heater will use.
y = 94.2kJ 


6 0
3 years ago
What is the most appropriate tool to use when collecting data from the investigation
NeTakaya
If it is just a reseach investigatory project, you could monitor it by using different variables (controlled), acurate measuring devices and camera for documentations
7 0
3 years ago
A solid uniform disk of diameter 3.20 m and mass 42 kg rolls without slipping to the bottom of a hill, starting from rest. If th
Korvikt [17]

Answer:

A(3.56m)

Explanation:

We have a conservation of energy problem here as well. Potential energy is being converted into linear kinetic energy and rotational kinetic energy.

We are given ω= 4.27rad/s, so v = ωr, which is 6.832 m/s. Place your coordinate system at top of the hill so E initial is 0.

Ef= Ug+Klin+Krot= -mgh+1/2mv^2+1/2Iω^2

Since it is a solid uniform disk I= 1/2MR^2, so Krot will be 1/4Mv^2(r^2ω^2=  v^2).

Ef= -mgh+3/4mv^2

Since Ef=Ei=0

Mgh=3/4mv^2

gh=3/4v^2

h=0.75v^2/g

plug in givens to get h= 3.57m

5 0
3 years ago
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