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3 years ago

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Penny placed a tablet of baking soda in a cup of water. The tablet immediately began to bubble, fizz, and eventually dissolve. D

id a physical or chemical change occur and how do you know?
A chemical; the fizzing sounds indicates a new substance was formed

B physical; the water can be boiled off and the tablet residue would be left

C physical; the tablet only dissolved in the water and formed a mixture

D chemical; the tablet gave off a gas in the form of bubbles

1 answer:

dangina [55]3 years ago

5 0

Answer:

D

Explanation:

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A right triangle has sides measuring 5 and 12 inches. If the two vectors have a magnitude of 5 and 12 and are at right angles to

ollegr [7]

Answer:

$x=13$

Explanation:

From the question we are told that

Magnitude 1 $M_1=5$

Magnitude 1 $M_2=12$

Generally the Pythagoras equation for the magnitudes is mathematically given as

$\sqrt{x^2}=\sqrt{M_1^2 +M_2^2}$

$\sqrt{x^2}=\sqrt{5^2 +12^2}$

$x=13$

Therefore resultant magnitude is

$x=13$

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3 years ago

A 40-cm-long tube has a 40-cm-long insert that can be pulled in and out. A vibrating tuning fork is held next to the tube. As th

Umnica [9.8K]

Answer:

The frequency of the tuning is 1.065 kHz

Explanation:

Given that,

Length of tube = 40 cm

We need to calculate the difference between each of the lengths

Using formula for length

$\Delta L=L_{2}-L_{1}$

$\Delta L=74.7-58.6$

$\Delta L=16.1\ m$

For an open-open tube,

We need to calculate the fundamental wavelength

Using formula of wavelength

$\lambda=2\Delta L$

Put the value into the formula

$\lambda=2\times16.1$

$\lambda=32.2\ cm$

We need to calculate the frequency of the tuning

Using formula of frequency

$f=\dfrac{v}{\lambda}$

Put the value into the formula

$f=\dfrac{343}{32.2\times10^{-2}}$

$f=1065.2\ Hz$

$f=1.065\ kHz$

Hence, The frequency of the tuning is 1.065 kHz

3 0

3 years ago

A person is using a rope to lower a 5.0-n bucket into a well with a constant speed of 2.0 m/s. What is the magnitude of the forc

OLga [1]

Answer:

5 N

Explanation:

The bucket is moving at a constant speed of 2m/s Therefore F=ma is 0 N for this to be correct the magnitude of the force exerted by the rope must be equal to the weight of the bucket which is 5 N

7 0

3 years ago

Read 2 more answers

An 20-cm-long Bicycle Crank Arm. With A Pedal At One End. Is Attached To A 25-cm-diameter Sprocket, The Toothed Disk Around Whic

malfutka [58]

To solve the problem, it is necessary to apply the concepts related to the kinematic equations of the description of angular movement.

The angular velocity can be described as

$\omega_f = \omega_0 + \alpha t$

Where,

$\omega_f =$ Final Angular Velocity

$\omega_0 =$ Initial Angular velocity

$\alpha =$ Angular acceleration

t = time

The relation between the tangential acceleration is given as,

$a = \alpha r$

where,

r = radius.

PART A ) Using our values and replacing at the previous equation we have that

$\omega_f = (94rpm)(\frac{2\pi rad}{60s})= 9.8436rad/s$

$\omega_0 = 63rpm(\frac{2\pi rad}{60s})= 6.5973rad/s$

$t = 11s$

Replacing the previous equation with our values we have,

$\omega_f = \omega_0 + \alpha t$

$9.8436 = 6.5973 + \alpha (11)$

$\alpha = \frac{9.8436- 6.5973}{11}$

$\alpha = 0.295rad/s^2$

The tangential velocity then would be,

$a = \alpha r$

$a = (0.295)(0.2)$

$a = 0.059m/s^2$

Part B) To find the displacement as a function of angular velocity and angular acceleration regardless of time, we would use the equation

$\omega_f^2=\omega_0^2+2\alpha\theta$

Replacing with our values and re-arrange to find $\theta,$

$\theta = \frac{\omega_f^2-\omega_0^2}{2\alpha}$

$\theta = \frac{9.8436^2-6.5973^2}{2*0.295}$

$\theta = 90.461rad$

That is equal in revolution to

$\theta = 90.461rad(\frac{1rev}{2\pi rad}) = 14.397rev$

The linear displacement of the system is,

$x = \theta*(2\pi*r)$

$x = 14.397*(2\pi*\frac{0.25}{2})$

$x = 11.3m$

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3 years ago

Decision making worksheet answer key

mario62 [17]

Answer:

<em><u>do </u></em><em><u>your</u></em><em><u> mom</u></em><em><u> hard</u></em><em><u> to</u></em><em><u> get</u></em><em><u> out</u></em><em><u> of</u></em><em><u> the</u></em><em><u> house</u></em><em><u> </u></em><em><u> you</u></em><em><u> doing</u></em><em><u> today</u></em><em><u> no</u></em><em><u> classes</u></em><em><u> are</u></em><em><u> you</u></em><em><u> doing</u></em><em><u> today</u></em><em><u> no</u></em><em><u> classes</u></em><em><u> are</u></em><em><u> you</u></em><em><u> doing</u></em><em><u> today</u></em><em><u> no</u></em><em><u> classes</u></em><em><u> are</u></em><em><u> not</u></em><em><u> sleeping</u></em><em><u> in</u></em><em><u> my</u></em><em><u> bed</u></em><em><u> you</u></em><em><u> have</u></em><em><u> any</u></em><em><u> best</u></em><em><u> to</u></em><em><u> get</u></em><em><u> the</u></em><em><u> meaning</u></em><em><u> do</u></em><em><u> you</u></em><em><u> want</u></em><em><u> for</u></em><em><u> it</u></em><em><u> is</u></em><em><u> my</u></em><em><u> friend</u></em><em><u> I</u></em><em><u> will</u></em><em><u> be</u></em><em><u> there</u></em><em><u> at</u></em><em><u> 12</u></em><em><u> I</u></em><em><u> have</u></em><em><u> send</u></em><em><u> me</u></em><em><u> a</u></em><em><u> </u></em><em><u>even</u></em><em><u> if</u></em><em><u> </u></em><em><u>we</u></em><em><u> </u></em><em><u>don't</u></em><em><u> ask</u></em><em><u> </u></em><em><u>everyone</u></em><em><u> </u></em><em><u>e</u></em><em><u> for</u></em><em><u> it</u></em><em><u> was</u></em><em><u> a</u></em><em><u> screenshot</u></em><em><u> I</u></em><em><u> am</u></em><em><u> </u></em><em><u>excited</u></em><em><u> </u></em><em><u>everything</u></em><em><u> </u></em><em><u>except</u></em><em><u> you</u></em><em><u> </u></em><em><u>eat</u></em><em><u> your</u></em><em><u> </u></em><em><u>eyes</u></em><em><u> </u></em><em><u>everything</u></em><em><u> </u></em><em><u>except</u></em><em><u> </u></em><em><u>everything</u></em><em><u> else</u></em><em><u> </u></em><em><u>ever</u></em><em><u> </u></em><em><u>even</u></em><em><u> </u></em><em><u>know</u></em><em><u> if</u></em><em><u> </u></em><em><u>everyone</u></em><em><u> e</u></em><em><u> </u></em><em><u>and</u></em><em><u> 10</u></em><em><u> </u></em><em><u>even</u></em><em><u> </u></em><em><u>though</u></em><em><u> it</u></em><em><u> </u></em><em><u>was</u></em><em><u> </u></em><em><u>kiss</u></em><em><u> emoji</u></em><em><u> </u></em><em><u>everything</u></em><em><u> </u></em><em><u>else</u></em><em><u> </u></em><em><u>ever</u></em><em><u> </u></em><em><u>eyebrows</u></em><em><u> </u></em><em><u>yet</u></em><em><u> I</u></em><em><u> </u></em><em><u>eat</u></em><em><u> </u></em><em><u>early</u></em><em><u> </u></em><em><u>to</u></em><em><u> get</u></em><em><u> </u></em><em><u>enough</u></em><em><u> </u></em><em><u>everything</u></em><em><u> </u></em><em><u>except</u></em><em><u> </u></em><em><u>everything</u></em><em><u> is</u></em><em><u> your</u></em><em><u> class</u></em><em><u> finish</u></em><em><u> up</u></em><em><u> </u></em><em><u>early</u></em><em><u> </u></em><em><u>enough</u></em><em><u> </u></em><em><u>even</u></em><em><u> know</u></em><em><u> what</u></em><em><u> is</u></em><em><u> going</u></em><em><u> on</u></em><em><u> with</u></em><em><u> out</u></em><em><u> hajab</u></em><em><u> I</u></em><em><u> have</u></em><em><u> send</u></em><em><u> it</u></em><em><u> out</u></em><em><u> to</u></em><em><u> </u></em><em><u>edit</u></em><em><u> a</u></em><em><u> video</u></em><em><u> on</u></em><em><u> </u></em><em><u>e</u></em><em><u> a</u></em><em><u> video</u></em><em><u> on</u></em><em><u> </u></em><em><u>each</u></em><em><u> </u></em><em><u>e</u></em>

Explanation:

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3 years ago