A I think I could be wrong I’m not good at this
The question is incomplete, the complete question is;
An alcohol thermometer makes use of alcohol's changing _______ in order to measure temperature. As the temperature goes up, the alcohol contained in the thermometer increases in volume, filling more of the thermometer's tube.
A.
mass
B.
state
C.
chemical composition
D.
density
Answer:
D.
density
Explanation:
Every kind of thermometer makes use of a change in a particular physical property of a substance as a measure of temperature. It must be a property that changes with temperature.
Density of a substance changes with temperature. Even though the mass of alcohol in glass remains constant, but its volume increases or decreases with change in temperature leading to a change in volume and consequently a change in density of the alcohol in glass. This change is used as a measure of the change in temperature.
Answer: Porous rock has gaps between rock particles that can fill with water. but i’m not 100% sure
Explanation:
Answer:
i going to be aniston i would say take a gess
Answer : The energy removed must be, 29.4 kJ
Explanation :
The process involved in this problem are :
![(1):C_6H_6(l)(322K)\rightarrow C_6H_6(l)(279K)\\\\(2):C_6H_6(l)(279K)\rightarrow C_6H_6(s)(279K)\\\\(3):C_6H_6(s)(279K)\rightarrow C_6H_6(s)(205K)](https://tex.z-dn.net/?f=%281%29%3AC_6H_6%28l%29%28322K%29%5Crightarrow%20C_6H_6%28l%29%28279K%29%5C%5C%5C%5C%282%29%3AC_6H_6%28l%29%28279K%29%5Crightarrow%20C_6H_6%28s%29%28279K%29%5C%5C%5C%5C%283%29%3AC_6H_6%28s%29%28279K%29%5Crightarrow%20C_6H_6%28s%29%28205K%29)
The expression used will be:
![Q=[m\times c_{p,l}\times (T_{final}-T_{initial})]+[m\times \Delta H_{fusion}]+[m\times c_{p,s}\times (T_{final}-T_{initial})]](https://tex.z-dn.net/?f=Q%3D%5Bm%5Ctimes%20c_%7Bp%2Cl%7D%5Ctimes%20%28T_%7Bfinal%7D-T_%7Binitial%7D%29%5D%2B%5Bm%5Ctimes%20%5CDelta%20H_%7Bfusion%7D%5D%2B%5Bm%5Ctimes%20c_%7Bp%2Cs%7D%5Ctimes%20%28T_%7Bfinal%7D-T_%7Binitial%7D%29%5D)
where,
= heat released for the reaction = ?
m = mass of benzene = 94.4 g
= specific heat of solid benzene = ![1.51J/g^oC=1.51J/g.K](https://tex.z-dn.net/?f=1.51J%2Fg%5EoC%3D1.51J%2Fg.K)
= specific heat of liquid benzene = ![1.73J/g^oC=1.73J/g.K](https://tex.z-dn.net/?f=1.73J%2Fg%5EoC%3D1.73J%2Fg.K)
= enthalpy change for fusion = ![-9.8kJ/mol=-\frac{9.8\times 1000J/mol}{78g/mol}=-125.6J/g](https://tex.z-dn.net/?f=-9.8kJ%2Fmol%3D-%5Cfrac%7B9.8%5Ctimes%201000J%2Fmol%7D%7B78g%2Fmol%7D%3D-125.6J%2Fg)
Now put all the given values in the above expression, we get:
![Q=[94.4g\times 1.73J/g.K\times (279-322)K]+[94.4g\times -125.6J/g]+[94.4g\times 1.51J/g.K\times (205-279)K]](https://tex.z-dn.net/?f=Q%3D%5B94.4g%5Ctimes%201.73J%2Fg.K%5Ctimes%20%28279-322%29K%5D%2B%5B94.4g%5Ctimes%20-125.6J%2Fg%5D%2B%5B94.4g%5Ctimes%201.51J%2Fg.K%5Ctimes%20%28205-279%29K%5D)
![Q=-29427.312J=-29.4kJ](https://tex.z-dn.net/?f=Q%3D-29427.312J%3D-29.4kJ)
Negative sign indicates that the heat is removed from the system.
Therefore, the energy removed must be, 29.4 kJ