Answer:
NaI
Explanation:
In I₂, HI and IBr, both atoms are nonmetals and they form covalent bonds in which electrons are shared.
In NaI, Na is a metal and I a nonmetal, so they form an ionic bond, where Na loses an electron to form Na⁺ and I gains an electron to form I⁻. Anions and cations are attracted to each other through electrostatic forces.
Since ionic bonds are stronger than covalent bonds, more energy is required to break them in the melting process, thus having higher melting points.
All in all, NaI is the one with the highest melting point.
Answer:
4P + 5O₂ —> P₄O₁₀
Explanation:
From the question given above, we obtained:
P + O₂ —> P₄O₁₀
The above equation can be balance as illustrated below:
P + O₂ —> P₄O₁₀
There are 4 atoms of P on the right side and 1 atom on the left side. It can be balance by 4 in front of P as shown below:
4P + O₂ —> P₄O₁₀
There are 10 atoms of O on the right side and 2 atoms on the left side. It can be balance by putting 5 in front of O₂ as shown below:
4P + 5O₂ —> P₄O₁₀
Now the equation is balanced.
No technically without buying anything your hair will not grow .
Answer:
28.0mL of the 0.0500M NaOH solution
Explanation:
<em>0.126g of lactic acid diluted to 250mL. Titrated with 0.0500M NaOH solution.</em>
<em />
The reaction of lactic acid, H₃C-CH(OH)-COOH (Molar mass: 90.08g/mol) with NaOH is:
H₃C-CH(OH)-COOH + NaOH → H₃C-CH(OH)-COO⁻ + Na⁺ + H₂O
<em>Where 1 mole of the acid reacts per mole of the base.</em>
<em />
You must know the student will reach equivalence point when moles of lactic acid = moles NaOH.
the student will titrate the 0.126g of H₃C-CH(OH)-COOH. In moles (Using molar mass) are:
0.126g ₓ (1mol / 90.08g) = <em>1.40x10⁻³ moles of H₃C-CH(OH)-COOH</em>
To reach equivalence point, the student must add 1.40x10⁻³ moles of NaOH. These moles comes from:
1.40x10⁻³ moles of NaOH ₓ (1L / 0.0500moles NaOH) = 0.0280L of the 0.0500M NaOH =
<h3>28.0mL of the 0.0500M NaOH solution</h3>
