A. Pyrite is an ore of gold and is used to jewelry making is a false statement
4,410 kJ
Explanation:
Gravitational Potential Enegry (GPE) is calculated as;
GPE = <em>m*g*h</em> where;
m = mass (kg)
g = gravity (m/s²)
h = height (meters)
= 90 * 9.8 * 5000
= 4,410,000 joules
= 4,410 kJ
Answer:
In the previous section, we discussed the relationship between the bulk mass of a substance and the number of atoms or molecules it contains (moles). Given the chemical formula of the substance, we were able to determine the amount of the substance (moles) from its mass, and vice versa. But what if the chemical formula of a substance is unknown? In this section, we will explore how to apply these very same principles in order to derive the chemical formulas of unknown substances from experimental mass measurements.
Explanation:
tally. The results of these measurements permit the calculation of the compound’s percent composition, defined as the percentage by mass of each element in the compound. For example, consider a gaseous compound composed solely of carbon and hydrogen. The percent composition of this compound could be represented as follows:
\displaystyle \%\text{H}=\frac{\text{mass H}}{\text{mass compound}}\times 100\%%H=
mass compound
mass H
×100%
\displaystyle \%\text{C}=\frac{\text{mass C}}{\text{mass compound}}\times 100\%%C=
mass compound
mass C
×100%
If analysis of a 10.0-g sample of this gas showed it to contain 2.5 g H and 7.5 g C, the percent composition would be calculated to be 25% H and 75% C:
\displaystyle \%\text{H}=\frac{2.5\text{g H}}{10.0\text{g compound}}\times 100\%=25\%%H=
10.0g compound
2.5g H
×100%=25%
\displaystyle \%\text{C}=\frac{7.5\text{g C}}{10.0\text{g compound}}\times 100\%=75\%%C=
10.0g compound
7.5g C
×100%=75%
Answer:
4.15×10⁻²¹ moles of Sn
Explanation:
This question can be solved by a simple rule of three.
We know that 1 mol contains 6.02×10²³ particles.
In this case, our particles are the atoms, so:
6.02×10²³ atoms / 1 mol . 2500 atoms = 4.15×10⁻²¹ moles.
The knowledge of mol can be applied for everything:
A mol of molecules
A mol of atoms
A mol of a compound
-470,809 m is in an integer