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Vlada [557]
3 years ago
5

Cortez's workout plan involves a total of 65 minutes of running and swimming. He burns 15 calories per minute when running and 6

calories per minute when swimming. Let r represent the amount of time he spends running. Write an expression to represent the amount of calories that he burns.
Physics
1 answer:
shutvik [7]3 years ago
4 0

Answer:

E=9r+390

Explanation:

<u>Function Modeling </u>

We can express the relations between different variables and magnitudes in mathematics formulas. This allows us to better manipulate the field data and even make predictions and take decisions out of them.

We know Cortez spends a total of 65 minutes of running and swimming. Let's call r the minutes of running and s the minutes of swimming. The first condition implies that

r+s=65

Or, equivalently

s=65-r

The energy burnt when running are 15 calories per minute. It means that he burns 15r in r minutes. Similarly, Cortez burns 6s calories when swimming. The total energy he burns is

E=15r+6s

Replacing the formula for s, we get

E=15r+6(65-r)

\boxed{E=9r+390}

That formula gives the total calories Cortez burns in r minutes of running

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Answer:

1. 21.66 Ohms

2.  3.38 A

3. 6.7 V

Explanation:

1. Req = 6+2 = 8 Ohms (2 and 6 are in a series circuit)

  Req = 1/8 +1/4 = 3/8 = 8/3 = 2.66 Ohms (8 and 4 are parallel, so we will add them using this equation)

  Req = 2.66 + 1 + 9 + 3 + 6 = 21.66 Ohms

2. I = V/R = 9/2.66 = 3.38 A (In a series circuit, the current is the same across the resistors, so we will add them and divided them by 9 volts)

3. V = IR = 3.38 x 2 = 6.7 V (In a series circuit, the voltage is different, so each resistor will have a different voltage.)

I hope this helps.  I am not an expert in physics but its ok :)

<u><em>Note: If the answer benefited u, mark me as the brainliest answer if u can, thx.</em></u>

3 0
2 years ago
A 5.67-kg block of wood is attached to a spring with a spring constant of 150 N/m. The block is free to slide on a horizontal fr
nikklg [1K]

Answer:

v=0.94 m/s

Explanation:

Given that

M= 5.67 kg

k= 150 N/m

m=1 kg

μ = 0.45

The maximum acceleration of upper block can be μ g.

 a= μ g                          ( g = 10 m/s²)

The maximum acceleration of system will ω²X.

ω = natural frequency

X=maximum displacement

For top stop slipping

μ g  =ω²X

We know for spring mass system natural frequency given as

\omega=\sqrt{\dfrac{k}{M+m}}

By putting the values

\omega=\sqrt{\dfrac{150}{5.67+1}}

ω = 4.47 rad/s

μ g  =ω²X

By putting the values

0.45 x 10 = 4.47² X

X = 0.2 m

From energy conservation

\dfrac{1}{2}kX^2=\dfrac{1}{2}(m+M)v^2

kX^2=(m+M)v^2

150 x 0.2²=6.67 v²

v=0.94 m/s

This is the maximum speed of system.

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