Answer:

0.124

Explanation:

We calculate the hydraulic gradient by the formulas below.

I = (change in h)/(change in l)-----eqn 1

I = (hk-hl)/change in L ----- equation 2

At k the headloss = hk,

At L the headloss = hL

The distance of water travel is change in I

Total head at k

hk = 543+23

= 566 ft

Total head at L

hL = 461+74

= 535 ft

Change in L = 250

When we substitute these values in equation 2

566-535/250

= 0.124

The hydraulic gradient is 0.124

**Answer:**

R = 1 kΩ

i_L = 2.2 mA

**Explanation:**

The complete question is given in attachment:

**Given:**

- The gain i_L / i_i = 11

- Given circuit Attachment

**Find:**

- Find the required value of R

- If the amplifier is fed with a current source having a current of 0.2 mA and a source resistance of 10 kΩ, find iL

**Solution:**

- Use KVL on right most loop (load loop):

v_x = 0 - i_i*10 = -10i_i

- Using ohm's law:

i = (0 - v_x) / R

i = 10*i_i / R

- Use KCL at the node:

i_L = i + i_i

- Substitute the the two i:

i_L = 10*i_i / R + i_i

i_L / i_i = ( 10/ R + 1 )

11 = ( 10/ R + 1 )

10 / R = 10

**R = 1 kΩ**

- The input resistance = 0 because there is a virtual ground at input. Then the value of source resistance will have no effect on resulting i_l, hence:

i_L = i_L / i_i * i_i

i_L = 11*0.2

**i_L = 2.2 mA **

**Answer:**

hello your question lacks the required diagram attached below is he missing diagram and solution

answer : 17480.618 Ib

**Explanation:**

To calculate the weight of block neccessary to prevent the gate from opening , we will first calculate the force of water from the hinge

next we will calculate moments about the force of water and the force about the hinge of the gate

attached below is the complete solution and free hand sketch

from the sketch : h1 = 7 ft, x = 2ft, h2 = 5ft,

No hablo espanol perdon amigo

**Answer:**

B. energy an object has because of its motion or position

**Explanation:**