Answer:
1.176
Explanation:
When the bullets impact the mass they become embedded on it, it is a plastic collision, therefore momentum is conserved.
v2 * (M + mb) = v1 * mb
Where
v1: muzzle velocity of the bullet
M: mass of the bob
mb: mass of the bullet
v2: mass of the bob with the bullet after being hit
v2 = v1 * mb / (M + mb)
Upon being impacted the bob will acquire speed v2, this implies a kinetic energy. The bob will then move and raise a height h. Upon acheiving the maximum height it will have a speed of zero. At that point all kinetic energy will be converted into potential energy.
Ek = 1/2 (M + mb) * v2^2
Ep = (M + mb) * g * h
Ek = Ep
1/2 (M + mb) * v2^2 = (M + mb) * g * h
1/2 * (v1 * mb / (M + mb))^2 = g * h
1/2 * v1^2 * mb^2 / (M + mb)^2 = g * h
v1^2 = g *h * (M+ mb)^2 / (1/2 * mb^2)
The height h that it reaches is related to the length L of the pendulum arm and the angle it forms with the vertical.
h = L * (1 - cos(a))
For the 9 mm:
For the 0.44 caliber:
The ratio is 460 / 391 = 1.176
Answer:
The electrical work for the process is 256.54 Btu.
Explanation:
From the ideal gas equation:
n = PV/RT
n is the number of moles of air in the tank
P is initial pressure of air = 50 lbf/in^2 = 50 lbf/in^2 × 4.4482 N/1 lbf × (1 in/0.0254m)^2 = 344736.2 N/m^2
V is volume of the tank = 40 ft^3 = 40 ft^3 × (1 m/3.2808 ft)^3 = 1.133 m^3
T is initial temperature of air = 120 °F = (120-32)/1.8 + 273 = 321.9 K
R is gas constant = 8.314 J/mol.k
n = 344736.2×1.133/8.314×321.9 = 145.94 mol
The thermodynamic process is an isothermal process because the temperature is kept constant.
W = nRTln(P1/P2) = 145.94×8.314×321.9×ln(50/25) = 145.94×8.314×321.9×0.693 = 270669 J = 270669 J × 1 Btu/1055.06 J = 256.54 Btu
Answer:
1. Changes in network topology or system configuration might bring security-related challenges. For example, adopting a new system configuration which is low in cost but also very new in the Industry might be vulnerable to the existing security.
2. New products or Services which are delivered to either the Internal/External users might be prone to security issues.
Let say a product 'A' has been launched by a company 'X' and for testing purpose it has been given to the internal users. Now as this product 'A' is a product of 'X' itself it will be allowed to carry in the official premises and if some user tries to hack this product and can make the product potentially harmful w.r.t security.
3. Consider a scenario where there is a change in management & team, the team members which were thoroughly responsible for Security kinds of stuff are dissolved into different teams. Also new members are hired for the team. Now, since the new members will need some time to get adapted to the Business As Usual things there are high chances of a security level not maintained as it was earlier by the old guys. This could be due to undocumented things in the organization or due to lack of Knowledge Transfer to the new joinees.
Answer:
The answer is below
Explanation:
1)
2)
3)
Because of the short, the resistance is zero.
4)
5)
6)
