<h3>
Answer:</h3>
29.467 g
<h3>
Explanation:</h3>
From the question;
Mass of copper is 200 g
Initial temperature of copper is 15°C
Mass of water is 200 grams
Initial temperature of water is 60°C
Final temperature of the mixture is 42.7 °C
We are required to calculate the mass of water
<h3>Step 1: Heat absorbed by copper </h3>
Quantity of heat, Q = Mass × specific heat capacity × change in temperature
Specific heat capacity of copper = 0.385 J/g°C
Change in temperature, ΔT = 42.7°C - 15°C
= 27.7° C
Q = mcΔT
Q = 200 g × 0.385 J/g°C × 27.7°C
= 2132.9 Joules
<h3>Step 2: Quantity heat released by water </h3>
Specific heat capacity of water is 4.184 J/g°C
Change in temperature, ΔT = 42.7°C - 60°C
= -17.3 °C
Assuming the mass of water is m
Then
Q = m × 4.184 J/g°C × 17.3 °C
= 72.3832m joules
<h3>Step 3: Calculating the mass of water </h3>
The heat gained by the copper metal is equal to the heat released by the water.
Therefore;
2132.9 Joules = 72.3832m Joules
m = 2132.9 J ÷ 72.3832 J
= 29.4668
= 29.467 g
Therefore, the mass of water is 29.467 g
