Oxidation half reaction is written as follows when using using reduction potential chart
example when using copper it is written as follows
CU2+ +2e- --> c(s) +0.34v
oxidasation is the loos of electron hence copper oxidation potential is as follows
cu (s) --> CU2+ +2e -0.34v
Magnets have batteries and the batteries make the magnets work it depends on which way the batteries are facing or if not im sorry and i hope this helped
I believe it would be better to use an orbital designation than the written configuration, if the number of electrons in the ground state of the atom are quite high for the given element, as above 50, for instance.
This saves space and also one can see the discrete quantized energy levels associated with the subshells of the main energy levels if written in orbital designation.
Answer:
The answer is 0.844/10 minutes
Explanation:
You have an enzyme that catalizes a reaction which gives a product that can be quantified by an absorbance measurement. The more reaction time, the more product quantity and higher absorbance.
The rate of the reaction is the change in products quantity per time unit. As you are using the absorbance as a measure of the product quantity, you can calculate the rate as the change in absorbance (ΔA) per time (in minutes) as follows:
rate= ΔA/time
rate= (final absorbance - initial absorbance) /minutes
rate= (0.444-0.022)/5 min
rate= 0.422/5 min
In 10 minutes will be :
rate= 0.844/10 min
Commonly, a rate is the relation between two quantities measured in different units. For example, the speed of a car is the change in meters (traveled distance) per time (m/s or km/h). For an enzyme, is the same (quantity of product/time).
Answer:
C,B,A
Explanation:
C has the most similar structure
B has the second most similar structure
A has the least similair structure
