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Elza [17]
3 years ago
5

How many ions form when 39 grams of calcium fluoride are added to excess water? a. 0.50 mol b. 1.0 mol c. 1.5 mol d. 3.0 mol

Chemistry
2 answers:
Sladkaya [172]3 years ago
7 0

Answer:

1.5 mol ions

Explanation:

agasfer [191]3 years ago
6 0

Answer:

c. 1.5 mol

Explanation:

  • Firstly, we need to calculate the no, of moles of 39.0 grams of calcium fluoride.

n = mass / molar mass = (39.0 g) / (78.07 g/mol) = 0.499 mol ≅ 0.5 mol.

  • CaF₂ ionized in water as:

<em>CaF₂ → Ca⁺² + 2F⁻.</em>

Every 0.1 mole of CaF₂ is ionized to 3 ions (1 ion of Ca⁺² and 2 ions of F⁻).

<em>So, 0.5 mol of CaF₂ will contain (3 x 0.5 mol = 1.5 mol) of ions.</em>

Thus, the right choice is "c. 1.5 mol".

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Calcium reacts with Hydrochloric acid to produce Calcium chloride and
hammer [34]

Answer:

Mass = 2.77 g

Explanation:

Given data:

Mass of HCl = 2 g

Mass of CaCl₂ produced = ?

Solution:

Chemical equation:

2HCl + Ca    →     CaCl₂ + H₂

Number of moles of HCl:

Number of moles = mass / molar mass

Number of moles = 2 g/ 36.5 g/mol

Number of moles = 0.05 mol

now we will compare the moles of HCl with CaCl₂.

                   HCl       :         CaCl₂

                     2         :          1

                   0.05     :       1/2×0.05 = 0.025 mol

Mass of CaCl₂:

Mass = number of moles × molar mass

Mass = 0.025 mol × 110.98 g/mol

Mass = 2.77 g

8 0
3 years ago
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Talja [164]
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5 0
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kvv77 [185]

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<h3>Further explanation</h3>

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Reaction

AB + CD⇒AD + CB

So for the option :

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Answer:

dk

Explanation:

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