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3 years ago

Ow is an electromagnet different from a bar magnet?

Physics

1 answer:

vladimir1956 [14]3 years ago

6 0

I think the answer is A or D

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The density of lead is 11.3 g/cm 3. What mass of lead is required to make a 1 cm 3 fishing sinker?

Aliun [14]

Answer:

11.3 g

Explanation:

given,

density of the lead = 11.3 g/cm³

volume = 1 cm³

mass of the lead = ?

we know,

$density=\dfrac{mass}{volume}$

mass = volume x density

mass = 1 x 11.3

mass = 11.3 g

hence, the mass of the lead is equal to 11.3 g

5 0

3 years ago

Read 2 more answers

In the refrigeration cycle, the process of liquid changing to the vapor phase _____.

Fiesta28 [93]

Evaporation? im not positive but im almost certain that's the answer

3 0

4 years ago

Read 2 more answers

-Para lograr que una pieza de 0,300 kg de cierto metal aumente su temperatura desde 40°C a 60 °C ha sido necesario suministrarle

marishachu [46]

Answer:

parte a) el calor específico es c = 0.383 J /(gr*K)

parte b) la temperatura inicial es T inicial= 52.72 °C

Explanation:

para el primer punto la formula para el calor Q es:

Q = m * c * ( T final - T inicial )

donde

m= masa de la pieza = 0.300 kg = 300 gr

Q = flujo de energía en forma de calor= 2299 J

c = calor específico

T final = temperatura final =40°C

T inicial = temperatura inicial = 60 °C

entonces

Q = m * c * ( T final - T inicial )

c = Q / [ m* ( T final - T inicial ) = 2299 J/[ 300 gr * ( 60 °C - 40°C )]

= 0.383 J /(gr*K)

c = 0.383 J /(gr*K)

para el segundo punto usamos la misma formula

Q = m * c * ( T final - T inicial )

pero

m= 200 gr= 0.200 kg

c=459.8 J/(kg*K) , Q =20.900 J , T final = 280 °C

Q = m * c * ( T final - T inicial )

T inicial = T final - Q/(m*c) =280 °C - 20.900 J/(459.8 J/(kg*K)* 0.200 kg) = 52.72 °C

7 0

4 years ago

A 45.00 kg person in a 43.00 kg cart is coasting with a speed of 19 m/s before it goes up a hill. there is no friction, what is

HACTEHA [7]

Answer:

the maximum vertical height the person in the cart can reach is 18.42 m

Explanation:

Given;

mass of the person in cart, m₁ = 45 kg

mass of the cart, m₂ = 43 kg

acceleration due to gravity, g = 9.8 m/s²

final speed of the cart before it goes up the hill, v = 19 m/s

Apply the principle of conservation of energy;

$mgh_{max} = \frac{1}{2}mv^2_{max}\\\\ gh_{max} = \frac{1}{2}v^2_{max}\\\\h_{max} = \frac{v^2_{max}}{2g} \\\\h_{max} =\frac{(19)^2}{2\times 9.8} \\\\h_{max} = 18.42 \ m$

Therefore, the maximum vertical height the person in the cart can reach is 18.42 m

5 0

3 years ago

What do we call the energy that is transferred to

mojhsa [17]

Answer:

Latent heat

Latent heat is the heat needed to change a state without a change in temperature.

Explanation:

Hope this helps :D

5 0

3 years ago