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Semmy [17]
4 years ago
15

The gravitational force between two objects is 45,000 N. What will be the gravitational force between the two objects if the dis

tance between the objects is reduced by one-half?
Physics
1 answer:
Nostrana [21]4 years ago
7 0

Answer:

180000 N

Explanation:

According to Newton's law of gravitation

F= G m1 m2 / r^2

This expression shows that if distance is reduced to half the gravitational force will increase 4 times.

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I know one answer is an observer on earth sees a lunar eclipse

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A science-fiction tale describes an artificial "planet" in the form of a band completely encircling a sun. The inhabitants live
arlik [135]

Answer:

8.97 days

Explanation:

Assuming we are asked what will be the period of revolution, this planet's year, in Earth days?

The period of revolution T is given as

T=2\pi\sqrt{\frac{r}{g} }

here, r= distance between planet and its sun which is same as distance between Earth-Sun = 149.7\times10^9 m

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therefore,

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13. If you have a 12 kg object, how do you find the weight?
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5 0
3 years ago
Relative to the ground, a car has a velocity of 15.3 m/s, directed due north. Relative to this car, a truck has a velocity of 22
bogdanovich [222]

Answer:

The magnitude of the truck's velocity relative to the ground is 35.82 m/s.

Explanation:

Given that,

Velocity of car relative to ground = 15.3 m/s

Velocity of truck relative to car = 22.5 m/s

We need to calculate the magnitude of the truck's velocity relative to the ground

We need to calculate the x component of the velocity

v_{x}=22.5\cos\theta

v_{x}=22.5\cos52^{\circ}

v_{x}=13.852\ m/s

We need to calculate the y component of the velocity

v_{y}=15.3+22.5\sin\theta

v_{y}=15.3+22.5\sin52^{\circ}

v_{y}=33.030\ m/s

Using Pythagorean theorem

|v|=\sqrt{v_{x}^2+v_{y}^2}

|v|=\sqrt{(13.852)^2+(33.030)^2}

|v|=35.82\ m/s

Hence, The magnitude of the truck's velocity relative to the ground is 35.82 m/s.

5 0
3 years ago
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