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Natali [406]
3 years ago
7

Calculate the

Physics
1 answer:
hammer [34]3 years ago
7 0
Acceleration of satlellite is :
a=(G*M_central)/R
R_Earth=6380km
h=500km
R=R_Earth +h=6880km
G=6,673*10^{-11} \frac{N m^{2} }{ kg^{2} }
M_central=5,98*10^{24}kg
a=(6,673*10^{-11} \frac{N m^{2} }{ kg^{2} }*5,98*10^{24}kg):6880=5,800078488*10^{10} \frac{m}{ s^{2} }
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"Force is applied to an object and the object is moved over a distance in the same direction of the applied force" is the defini
DaniilM [7]
I believe this is gravitational force

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3 years ago
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A block of mass m = 1.5 kg is released from rest at a height of H = 0.81 m on a curved frictionless ramp. At the foot of the ram
kogti [31]

Answer:

0.31 m

Explanation:

m = mass of the block = 1.5 kg

H = height from which the block is released on ramp = 0.81 m

k = spring constant of the spring = 250 N/m

x = maximum compression of the spring

using conservation of energy

Spring potential energy gained by spring = Potential energy lost by block

(0.5) k x² = mgH

(0.5) (250) x² = (1.5) (9.8) (0.81)

x = 0.31 m

7 0
4 years ago
8. Which phase of matter is most common in the
nasty-shy [4]
A. Plasma
That is your answer!
4 0
3 years ago
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is dimensionally correct relation necessarily to be a correct physical relation? explain with example.​
Andreas93 [3]

Answer: hope it helps you...❤❤❤❤

Explanation: If your values have dimensions like time, length, temperature, etc, then if the dimensions are not the same then the values are not the same. So a “dimensionally wrong equation” is always false and cannot represent a correct physical relation.

No, not necessarily.

For instance, Newton’s 2nd law is  F=p˙ , or the sum of the applied forces on a body is equal to its time rate of change of its momentum. This is dimensionally correct, and a correct physical relation. It’s fine.

But take a look at this (incorrect) equation for the force of gravity:

F=−G(m+M)Mm√|r|3r  

It has all the nice properties you’d expect: It’s dimensionally correct (assuming the standard traditional value for  G ), it’s attractive, it’s symmetric in the masses, it’s inverse-square, etc. But it doesn’t correspond to a real, physical force.

It’s a counter-example to the claim that a dimensionally correct equation is necessarily a correct physical relation.

A simpler counter example is  1=2 . It is stating the equality of two dimensionless numbers. It is trivially dimensionally correct. But it is false.

4 0
4 years ago
What is the final velocity of the ball that is dropped from a height of 200m?
Hoochie [10]

The final velocity of the ball that is dropped from a height of 200m is v = 44.73 m/s .

<h3>What is velocity with example?</h3>

The rate at which an object is travelling in one direction is referred to as its velocity. an automobile traveling north on a highway, or a rocket taking off. Its velocity vector's absolute value always is equal to the motion's speed because it is a scalar.

<h3>Briefing:</h3>

Given the initial velocity of the ball (u) =  0

Distance travelled by the ball (s) = 200m

Acceleration (a) = 10 m/s²

As we know:

v² = u² + 2as

Putting values:

v² = 0+2 × (10 m/s²) × (200 m)

v = 44.73 m/s.

To know more about Velocity visit:

brainly.com/question/18084516

#SPJ9

8 0
1 year ago
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