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Goshia [24]
3 years ago
15

8. Which phase of matter is most common in the

Physics
2 answers:
Arturiano [62]3 years ago
8 0

Answer:

plasma

Explanation:

Cause in the universe many exist in either in gaseous or plasma form but plasma is greater

nasty-shy [4]3 years ago
4 0
A. Plasma
That is your answer!
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If a girl is standing still and holding a box, is she doing any work? (No)
SpyIntel [72]

Answer:

gravity

Explanation:

7 0
2 years ago
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4. Uncle Harry weighs 180 pounds. What is his mass in kilograms?
MatroZZZ [7]
180 pounds (lb) converts to 81.647 kilograms (kg).
5 0
2 years ago
A water heater that has the shape of a right cylindrical tank with a radius of 1 foot and a height of 4 feet is being drained. h
Natali5045456 [20]

<span> </span>For any prism-shaped geometry, the volume (V) is assumed by the product of cross-sectional area (A) and height (h). 

<span> V = Ah </span>

<span>
Distinguishing with respect to time gives the relationship between the rates. 
dV/dt = A*dh/dt</span>

<span> in the meantime the area is not altering </span>

<span>
dV/dt = π*(1 ft)^2*(-0.5 ft/min) </span>

<span>
dV/dt = -π/2 ft^3/min ≈ -1.571 ft^3/min 

Water is draining from the tank at the rate of π/2 ft^3/min.</span>

5 0
3 years ago
) A striker can give the ball an initial speed of 30m/s. Within what two elevation angles must he kick
sveticcg [70]

Answer:

  about 19.6° and 73.2°

Explanation:

The equation for ballistic motion in Cartesian coordinates for some launch angle α can be written ...

  y = -4.9(x/s·sec(α))² +x·tan(α)

where s is the launch speed in meters per second.

We want y=2.44 for x=50, so this resolves to a quadratic equation in tan(α):

  -13.6111·tan(α)² +50·tan(α) -16.0511 = 0

This has solutions ...

  tan(α) = 0.355408 or 3.31806

The corresponding angles are ...

  α = 19.5656° or 73.2282°

The elevation angle must lie between 19.6° and 73.2° for the ball to score a goal.

_____

I find it convenient to use a graphing calculator to find solutions for problems of this sort. In the attachment, we have used x as the angle in degrees, and written the function so that x-intercepts are the solutions.

5 0
2 years ago
The bar graph shows the population of male and female deer in a forest, measured in 10-year intervals. According to the graph, w
saul85 [17]

Answer: option D. the ratio of the population of male deer is not constant.


Explanation:


The bar graph permits to compare the results for two different populations: male and female deer in a very easy visual way.


These features are remarkable:


  • The polulation of male deer (blue bars) decrease from 1961 to 1971, then increase in the next 10 year, decrease in the next decade, and increase for the next two decades. So, its trend is erratic, with ups and downs.

        This discards the option A, which states that the population of male deer increases each decade from 1961 to 2011.


  • The population of female deer (purple or brown bars) decreases every decade.

        This discards the option B. which states that when the polulation of male deer increases, the poluplation of female deer also increases.


  • The populations never are equal, hence this discards the option C.

  • Since, one popultion increases and decreases, while the other population only decreases, you conclude that the ratio of the population of male deer to female deer is not constant, which is the option D.
4 0
3 years ago
Read 2 more answers
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