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Stels [109]
4 years ago
10

Give the complete electronic configuration for oxygen. 1s22s22px22pz2 1s22s22px4 1s22s22py22pz2 1s22s22px22py2 1s22s22px22py12pz

1
Chemistry
1 answer:
9966 [12]4 years ago
8 0
Oxygen- atomic number 8
1s² 2s² 2px² 2py¹ 2pz¹
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PLEASE I NEED THIS ANSWERED IN 5 MINS
yKpoI14uk [10]
The answer would be: C.  160.3 J/mol*K 

To solve this question, you need to know the equation for Gibbs free energy formula. Entropy is expressed as delta S. The temperature would be expressed as T. Don't forget that temperature use Kelvin as unit, not Celsius

The formula would be:
G= H- T*S
130.5 kJ/mol= 178.3kJ/mol - (25+273.15K)*S
(298.15K)*S=178.3kJ/mol - 130.5 kJ/mol
S= (47.8kJ/mol)/ 298.15K=
S= 0.1603 kJ/mol*K= 160.3 J/mol*K        ------> 1kJ= 1000J
4 0
3 years ago
Using the following equation how many moles of KClO3 are required if 6.9 moles of O2 are formed?
Nimfa-mama [501]

Answer:

Number of moles of KClO3 required to produce 6.9 moles of oxygen gas is 4.6 moles.

Explanation:

The decomposition of potassium trioxochlorate(v) by heat to produce potassium chloride and oxygen gas is given by the balanced chemical equation below;

2KClO3(s) ----> 2KCl(s) + 3O2(g)

From the equation of the reaction, 2 moles of KClO3 produces 3 moles of oxygen gas when it decomposes under standard conditions of temperature and pressure.

The mole ratio of KClO3 to oxygen gas

is 2:3

When 6.9 moles of oxygen gas is produced, (2/3) * 6.9 moles of KClO3 will be required = 4.6 moles of KClO3

Therefore, number of moles of KClO3 required to produce 6.9 moles of oxygen gas is 4.6 moles

6 0
3 years ago
Is the reaction above a replacement reaction? Explain.
Lerok [7]
Replacement I don't see anything
4 0
3 years ago
exactly 1mol of n2o4 is placed in an empty 1 l container. if at equilibrium n2o4 is dissociated 20%, what is the value of equili
egoroff_w [7]

Answer:

K = 0.2

Explanation:

Based on the chemical dissociation of N₂O₄:

N₂O₄ ⇄ 2NO₂

The equilibrium constant, K, of the reaction is:

K = [NO₂]² / [N₂O₄]

Now, if 20% of N₂O₄ is dissociated, 80% remains as N₂O₄ = 0.8mol/L = 0.8M

as 20% is dissociated, 0.2moles of N₂O₄ were dissociated and 0.2*2 = 0.4mol/L of NO₂ are produced.

Replacing in K:

K = [0.4M]² / [0.8M]

<h3>K = 0.2</h3>
5 0
3 years ago
Which is true about sugar dissolving in water?
AfilCa [17]
Sugar is the solute since it is the thing that is being dissolved.
And the water is the solvent since it is the thing that contains the solute.
 
7 0
3 years ago
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