Answer and Explanation:
The resonance contributor in cyclopentadienone (as shown in the attachment below) results into the compound having a positive charge on the carbonyl group, C=O which accounts for a highly reactive anti-aromatic 4π system. And this illustrates the reason for its instability.
Answer:
Mass of NaBr produced = 23.67 g
Explanation:
Given data:
Mass of AgBr = 42.7 g
Mass of NaBr produced = ?
Solution:
Chemical equation:
2Na₂S₂O₃ + AgBr → NaBr + Na₃(Ag(S₂O₃)₂
Number of moles of AgBr:
Number of moles = mass/molar mass
Number of moles = 42.7 g/ 187.7 g/mol
Number of moles = 0.23 mol
now we will compare the moles of AgBr with NaBr.
AgBr : NaBr
1 : 1
0.23 : 0.23
Mass of NaBr:
Mass = number of moles × molar mass
Mass = 0.23 mol × 102.89 g/mol
Mass = 23.67 g
<h3><u>Answer;</u></h3>
<h3><u>Explanation;</u></h3>
- Bead is a drug fashioned into small, round objects that dissolve gradually to release the drug slowly
-
Pellet is a drug fashioned into small, bullet-shaped objects that dissolve gradually to release the drug slowly
-
Wafer is a drug fashioned into a thin disk that dissolves gradually to release the drug slowly
Answer:
A)glyceraldehyde 3-phosphate dehydrogenase reaction,
B)Thehexose bisphosphate that accumulates is fructose 1,6-bisphosphate
C)glyceraldehyde 3-phosphate dehydrogenase reaction to yield an acyl arsenate
Explanation:
The fermentation of ethanol in yeast has the following overall equation Glucose 2ADP 2Pi88n2 ethanol 2CO22ATP 2H2O which makes it clear that phosphate is required for the continued operation of glycolysis and formation of ethanol . In extracts to which glucose is added, fermentation proceeds until ADP and Pi(present in the extracts) are exhausted.(a)Phosphate is required in the glyceraldehyde 3-phosphate dehydrogenase reaction, and glycolysis will stop at this step when Piis exhausted. Because glucose remains, it will be phosphorylated by ATP, but Piwill not be released.(b)Fermentation in yeast cells produces ethanol and CO2rather than lactate . Without these reactions (in the absence of oxygen), NADH would accumu-late and no new NADwould be available for further glycolysis ). Thehexose bisphosphate that accumulates is fructose 1,6-bisphosphate; in terms of energet-ics, this intermediate lies at a “low point” or valley in the pathway, between the energy-input reactions that precede it and the energy-payoff reactions that follow.(c)Arsenate replaces Piin the glyceraldehyde 3-phosphate dehydrogenase reaction to yieldan acyl arsenate, which spontaneously hydrolyzes. This prevents formation of fructose1,6-bisphosphate and ATP but allows formation of 3-phosphoglycerate, which continuesthrough the pathway.
