Answer:
H_w = 2.129 m
Explanation:
given,
Width of the weir, B = 1.2 m
Depth of the upstream weir, y = 2.5 m
Discharge, Q = 0.5 m³/s
Weir coefficient, C_w = 1.84 m
Now, calculating the water head over the weir




now, level of weir on the channel
H_w = y - H
H_w = 2.5 - 0.371
H_w = 2.129 m
Height at which weir should place is equal to 2.129 m.
Answer:
change in y = -7
change in x = -17
magnitude of displacement = sqrt(7^2+17^2)
tan of angle below -x axis = 7/17
because in third quadrant where x and y are negative
Answer:
10 Kg
Explanation:
Force is equal to mass times acceleration
therefore mass is equal to force divided by acceleration
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The right answer is B. hope this helps you :)