C₀=2 mol/l
c₁=0.400 mol/l
v₁=100.0 ml = 0.1 l
c₁v₁=c₀v₀
v₀=c₁v₁/c₀
v(H₂O)=v₁-v₀
v₀=0.1*0.400/2=0.02 l = 20 ml
v(H₂O)=100 - 20 = 80 ml
It is necessary to mix 20 ml of the feed solution and 80 ml of water.
Answer:
The molarity of this final solution is 0.167 M
Explanation:
Step 1: Data given
Volume of a 0.100 M HNO3 solution = 50.0 mL
Volume of a 0.200 M HNO3 = 100.0 mL
Step 2: Calculate moles
The final molarity must lie between 0.1M and 0.2M
Moles = molarity * volume
Moles HNO3 in 50mL of a 0.100M solution = 0.05 L *0.100 M = 0.005 mol
Moles HNO3 in 100mL of a 0.200M solution = 0.100 L*0.200 = 0.020mol
total moles = 0.005+0.020 = 0.025 moles in 150mL solution = 0.150L
Step 3: Calculate molarity of final solution
Molarity = mol / volume
Molarity 0.025 moles /0.150 L
Molarity = 0.167M
The molarity of this final solution is 0.167 M
A mole of a substance is defined as: The mass of substance containing the same number of fundamental units as there are atoms in exactly 12.000g of 12C. Fundamental units change depending on the substance.
C. The number of neutrons
Since Carbon 12 has 6 neutrons
And carbon 13 has 7 neutrons.
You know that elements have equal protons (atomic number) and electrons
