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8090 [49]
3 years ago
6

When the concentration of solute in a solid solution exceeds its solubility limit, a new solid solution or phase forms that has

a composition distinctly different than the original solid solution?
Chemistry
1 answer:
soldi70 [24.7K]3 years ago
8 0
Answer is: true.
Solid solution <span>is a </span>solid state solution<span> of one or more </span>solutes<span> in a </span>solvent or <span>mixture of two </span>crystalline<span> solids that coexist as</span> crystal lattice. <span>Examples of solid solutions are metal </span>alloys (<span>mixture of </span>metals<span> or a mixture of a metal and another </span>element), semiconductors and moist<span> solids. </span>
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Valance shell example..​
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Answer:

<h2>Oxygen has six valence electrons, two in the 2s subshell and four in the 2p subshell.</h2>

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<h3>Configuration of oxygen's valence electrons as 2s²2p⁴.</h3>

Explanation:

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The three conditions that encourage the presence of marine life in the ocean are proximity to land, water depth and ____________
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Which of the following methods can be used to determine the relative age of rock and strata? Select all that apply.
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For double-helix formation, DG can be measured to be 2 54 kJ mol 1 ( 2 13 kcal mol 1 ) at pH 7.0 in 1 M NaCl at 25 8C (298 K). T
levacccp [35]

Answer:

ΔS = -661.0J/mol is the entropy change for the system

ΔS = -842J/mol.K is the entropy change for the surroundings

Explanation:

From the relationship between ΔG, T, ΔH and ΔS,

Mathematically, ΔG = ΔH - TΔS

TΔS = ΔH - ΔS

ΔS = ΔH - ΔS / T

but ΔG = -54 kJ/mol, ΔH = -251 kJ/mol and T = 25 °C (298 K)

plugging into the equation,

ΔS = -251 kJ/mol - ( -54 kJ/mol) / 298

ΔS  = -0.6610KJ/mol or in J.mol

ΔS = -661.0J/mol is the entropy change for the system

  • For entropy change for the surroundings = ΔS = ΔH/T
  • ΔS  = -251 kJ/mol / 298K
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Answer:Lithium

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