Answer:
0.718L of 0.81M HCl are required
Explanation:
Based on the reaction:
Cd(s)+2HCI(aq) → H2(g)+CdCl2(aq)
<em>1 mol of Cd reacts with 2 moles of HCl</em>
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To solve this question we must, as first, find the moles of Cd. With the moles of Cd we can find the moles of HCl needed to react completely with the Cd. With the moles and the molarity we can find the volume:
<em>Moles Cd -Molar mass: 112.411g/mol-:</em>
32.71g * (1mol / 112.411g) = 0.2910 moles Cd
<em>Moles HCl:</em>
0.2910 moles Cd * (2 moles HCl / 1mol Cd) =
0.5820 moles HCl
<em>Volume:</em>
0.5820 moles HCl * (1L / 0.81moles) =
<h3>0.718L of 0.81M HCl are required</h3>
Answer:
pH = 12.5
Explanation:
The reaction that takes place is
- 2OH⁻(aq) + Pb⁺²(aq) → Pb(OH)₂(s)
The OH⁻ species come from the metal hydroxide of the solution, and Pb(OH)₂ is the precipitate.
Now we <u>convert 3.81 grams of Pb(OH)₂ into moles</u>, using its <em>molar mass</em>:
- 3.81 g ÷ 241.12 g/mol = 0.0158 mol Pb(OH)₂
Now we <u>convert 0.0158 Pb(OH)₂ moles into OH⁻ moles</u>, using the <em>stoichiometric coefficients of the reaction</em>:
- 0.0158 mol Pb(OH)₂ *
= 0.0316 mol OH⁻
With the given concentration (1 L), we <u>calculate [OH⁻]</u>:
- [OH⁻] = 0.0316 mol / 1 L = 0.0316 M
Then we <u>calculate the pOH</u> of the solution:
And finally we <u>calculate the pH</u>:
Answer:
see Explanation
Explanation:
it forms a layer over the metal and when removed the metal has been protected from other elements
Answer:
C. Because my teacher said so
Hope this helps :)