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gizmo_the_mogwai [7]
3 years ago
9

Quick question.

Chemistry
1 answer:
Minchanka [31]3 years ago
5 0

Solution:- Halogens are fluorine, chlorine, bromine, iodine and Astatine(F, Cl, Br, I and At) and these are present in the 7A group of the periodic table. In modern periodic table this group is written as 17th group. This group elements have 7 valence electrons and so they are in group 7A.

So, the right choice is D. 7A.

You might be interested in
Please help asap :(
Ludmilka [50]

Answer:

6.32g

Explanation:

The mass of 1 mol of K is 40g, and the reaction needs 2 moles of K to produce 2 moles of KCl, so it needs 80g of K to produces 151g of KCl.

So you make a rule of three:

x = 3.35•151/80

x = 6.32g

3 0
3 years ago
The density of liquid mercury is 13.5 g/cm^3. What mass of mercury (in kg) is required to fill a hollow cylinder having an inner
olya-2409 [2.1K]

Answer: 1.06 kg

Explanation:

Density is defined as the mass contained per unit volume.

Density=\frac{mass}{Volume}

Given :

Density of mercury = 13.5g/cm^3

volume of cylinder  = volume of mercury = \pir^2h

where r = radius of cylinder = \frac{diameter}{2}=\frac{2cm}{2}=1cm

h= height = 25.0 cm

Putting in the values we get:

volume of mercury =3.14\times 1^2\times 25=78.5cm^3

mass=density\times volume=13.5g/cm^3\times 78.5cm^3=1059.75g=1.06kg      (1kg=1000g)

Thus mass of mercury required to fill a hollow cylinder having an inner diameter of 2.00 cm to a height of 25.0 cm is 1.06 kg.

4 0
3 years ago
A small bubble rises from the bottom of a lake where the temperature and pressure are 4.0 C and 3.0 atm, to the water’s surface,
Varvara68 [4.7K]

Answer:

The final volume of the bubble is 7.13 mL.

Explanation:

The combined gas equation is,

\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}

where,

P_1 = initial pressure of gas = 3 atm

P_2 = final pressure of gas = 0.95 atm

V_1 = initial volume of gas = 2.1 mL=0.0021 L

V_2 = final volume of gas = ?

T_1 = initial temperature of gas = 4^oC=273.15+4K=277.15 K

T_2 = final temperature of gas = 25^oC=273.15+25 k=298 .15 K

Now put all the given values in the above equation, we get:

\frac{3 atm\times 0.0021 L}{277.15 K}=\frac{0.95 atm\times V_2}{298.15 K}

V_2=\frac{3 atm\times 0.0021 L\times 298.15 K}{277.15 K\times 0.95 atm}=0.00713 L = 7.13 mL

The final volume of the bubble is 7.13 mL.

5 0
3 years ago
2k+Cl2=2KCI how many grams of KCl is produced from 8.50 g of K and excess Cl2
ZanzabumX [31]

Answer:

Mass = 16.4 g

Explanation:

Given data:

Mass of K = 8.50 g

Mass of KCl produced = ?

Solution:

Chemical equation:

2K + Cl₂     →    2KCl

Number of moles of K:

Number of moles = mass/ molar mass

Number of moles = 8.50 g/ 39 g/mol

Number of moles = 0.22 mol

Now we will compare the moles of potassium and potassium chloride.

                  K         :        KCl

                  2         :          2

                0.22      :        0.22

Mass  of KCl:

Mass = number of moles × molar mass

Mass = 0.22 mol × 74.55 g/mol

Mass = 16.4 g

4 0
3 years ago
Which of the following best describes weight? The amount of space an object takes up The amount of matter in an object The force
Alenkasestr [34]
The force of an object due mass and gravity.it can also be defined as the force exerted by gravity on a body
4 0
3 years ago
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