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Sergeu [11.5K]
3 years ago
15

_Na3PO4 + __KOH → _NaOH + ___K3PO4

Chemistry
2 answers:
KATRIN_1 [288]3 years ago
8 0
Jdndjdnndndndjxjjxnxnxnxjjxjxjdjdjdjdjdjjdjdhdudhshdhdhhdhdhdhhfhffh
arlik [135]3 years ago
5 0
1, 3, 1, 3 you can use the app chemical balanced
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Why do electrons transition between energy levels within the atom, and how do we detect these transitions?
Sedaia [141]

Answer:

See explanation

Explanation:

Electrons transition between energy levels in an atom due to gain or loss of energy. An electron may gain energy and move from its ground state to one of the accessible excited states. The electron quickly returns to ground state, emitting the energy previously absorbed as a photon of light. The wavelength of light emitted is measured using powerful spectrometers.

Atoms can be excited thermally or by irradiation with light of appropriate frequency.

7 0
3 years ago
When a 0.4500 g sample of impure potassium chloride was dissolved in water and treated with an excess ofsilver nitrate, 0.8402 g
Svetllana [295]

Answer:

97.78% KCl in the original sample

Explanation:

5 0
3 years ago
In the reaction N2(g) + O2(g) 2NO(g), how will increasing pressure on the system affect the equilibrium?
Leno4ka [110]
The pressure increase does not affect the equilibrium shift reaction.
4 0
4 years ago
Read 2 more answers
Write the chemical formula for the anion present in the aqueous solution of Pb(C2H3O2)2
yKpoI14uk [10]

Pb(C₂H₃O₂)₂ is lead(II) acetate

Pb(C₂H₃O₂)₂ --> Pb²⁺ + C₂H₃O₂²⁻

Lead(II) acetate ionizes in aqueous solution to form lead cation and acetate anion.

The chemical formula for the anion present in the aqueous solution of Pb(C₂H₃O₂)₂ is C₂H₃O₂²⁻

C₂H₃O₂²⁻ or CH₃COO⁻ is called the acetate ion.

Therefore, the correct answer is C₂H₃O₂²⁻

3 0
3 years ago
Read 2 more answers
A 2.04 g lead weight, initially at 10.8 oC, is submerged in 7.62 g of water at 52.3 oC in an insulated container. clear = 0.128
alisha [4.7K]

Answer: The final temperature of both the weight and the water at thermal equilibrium is 50.26^{o}C.

Explanation:

The given data is as follows.

mass = 7.62 g,           T_{2} = 10.8^{o}C

Let us assume that T be the final temperature. Therefore, heat lost by water is calculated as follows.

       q = mC \times \Delta T    

          = 7.62 g \times 4.184 J/^{o}C \times (52.3 - T)

Now, heat gained by lead will be calculated as follows.

       q = mC \times \text{Temperature change of lead}  

           = 2.04 \times 0.128 \times (T - 11.0)

According to the given situation,

     Heat lost = Heat gained

7.62 g \times 4.184 J/^{o}C \times (52.3 - T) = 2.04 \times 0.128 \times (T - 11.0)

        T = 50.26^{o}C

Thus, we can conclude that the final temperature of both the weight and the water at thermal equilibrium is 50.26^{o}C.

7 0
4 years ago
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