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Luden [163]
3 years ago
13

Write a nuclear equation for the formation of iron-54 through fusion

Chemistry
2 answers:
maksim [4K]3 years ago
7 0
Fe + heat ----> Fe_54 + + neutrons
dimulka [17.4K]3 years ago
3 0

Answer: _{24}^{50}\textrm{Cr}+_2^4\textrm{He}\rightarrow _{26}^{56}\textrm{Fe}

Explanation:

Nuclear fusion : It is a process which involves the conversion of two small nuclei to form a heavy nuclei along with release of energy.

Nuclear fission : It is a process which involves the conversion of a heavier nuclei into two or more small and stable nuclei along with the release of energy.

The nuclear fusion reaction for the formation of iron-54 involves fusion of chromium with a alpha particle to produce iron.

The balanced nuclear reaction will be:

_{24}^{50}\textrm{Cr}+_2^4\textrm{He}\rightarrow _{26}^{56}\textrm{Fe}

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A 5.00 mL sample of hydrochloric acid is titrated with 0.1293 M ammonia (a base). If the titration required 28.15 mL of ammonia,
Sladkaya [172]

Answer:

1. C = 0.73 M.

2. pH = 0.14

       

Explanation:

The reaction is the following:

HCl + NH₃ ⇄ NH₄⁺Cl⁻

From the titration, we can find the number of moles of HCl that were neutralized by the ammonia.

n_{a} = n_{b}

Where "a" is for acid and "b" is for base.

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Hence the initial concentration of the acid is 0.73 M.

The original pH of the acid is given by:

pH = -log([H^{+}])

pH = -log(0.73) = 0.14          

Therefore, the original pH of the acid is 0.14.

I hope it helps you!                  

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