D. Lithium or Li has the smallest ionization energy of those listed with an energy of 5,3917.
I hope that helps u!
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I can’t see the whole question......
The answer would be 560,848,164 because the 0 at the start WOULDNT matter
Answer:
Y = 92.5 %
Explanation:
Hello there!
In this case, since the reaction between lead (II) nitrate and potassium bromide is:

Exhibits a 1:2 mole ratio of the former to the later, we can calculate the moles of lead (II) bromide product to figure out the limiting reactant:

Thus, the limiting reactant is the KBr as it yields the fewest moles of PbBr2 product. Afterwards, we calculate the mass of product by using its molar mass:

And the resulting percent yield:

Regards!