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alexira [117]
3 years ago
13

According to the rate law, how do concentrations affect rate?

Chemistry
2 answers:
AVprozaik [17]3 years ago
7 0

Explanation:

According to rate law, rate of a reaction depends upon the concentration of the species participating in the reaction.

For example,        xA + yB \rightarrow Products

                         Rate \propto k[A]^{x}[B]^{y}

                            Rate = k[A]^{x}[B]^{y}

Therefore, when there is increase in concentration of reactants then there will be more number of collisions. Due to this there will rapid formation of products. Hence, rate of reaction will increase.

Whereas decrease in concentration of reactants will decrease the rate of a reaction.

jekas [21]3 years ago
4 0
Higher the concentration, the faster the reaction would occur thus higher the rate because there would be more amount of reactants for the reaction to occur and more particles would frequently collide to produce the products quickly.
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Taking into account the definition of avogadro's number, 3.37×10⁻⁷ moles of methane are 20.32×10¹⁶ molecules.

First of all, you have to know that Avogadro's number indicates the number of particles of a substance (usually atoms or molecules) that are in a mole.

Its value is 6.023×10²³ particles per mole and it applies to any substance.

Then you can apply the following rule of three: if 6.023×10²³ molecules are contained in 1 mole of methane, then 20.32×10¹⁶ molecules are contained in how many moles of methane?

amount of moles of methane= (20.32×10¹⁶ molecules × 1 mole)÷ 6.023×10²³ atoms

Solving:

<u><em>amount of moles of methane= 3.37×10⁻⁷ moles</em></u>

Finally, 3.37×10⁻⁷ moles of methane are 20.32×10¹⁶ molecules.

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2 years ago
At a cost of $1600/oz, how much would you have to pay for a solid cubic foot of gold?
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We'll begin by calculating the mass in ounce (oz) of a cube foot (ft³) of gold. This can be obtained as follow:

<h3 />

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<h3>Mass of gold =?</h3>

Density = mass /volume

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<h3>Mass of gold = 19298 oz</h3>

Finally, we shall determine the cost of 19298 oz of gold. This can be obtained as follow:

1 oz = $ 1600

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19298 oz = 19298 × 1600

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Therefore, a solid cube foot of gold (i.e 19298 oz) will cost $ 30876800

Learn more: brainly.com/question/15407624

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