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alexira [117]
3 years ago
13

According to the rate law, how do concentrations affect rate?

Chemistry
2 answers:
AVprozaik [17]3 years ago
7 0

Explanation:

According to rate law, rate of a reaction depends upon the concentration of the species participating in the reaction.

For example,        xA + yB \rightarrow Products

                         Rate \propto k[A]^{x}[B]^{y}

                            Rate = k[A]^{x}[B]^{y}

Therefore, when there is increase in concentration of reactants then there will be more number of collisions. Due to this there will rapid formation of products. Hence, rate of reaction will increase.

Whereas decrease in concentration of reactants will decrease the rate of a reaction.

jekas [21]3 years ago
4 0
Higher the concentration, the faster the reaction would occur thus higher the rate because there would be more amount of reactants for the reaction to occur and more particles would frequently collide to produce the products quickly.
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What is Keq for the reaction N₂ + 3H2 = 2NH3 if the equilibrium
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The Keq for the reaction N₂ + 3H2 = 2NH3 if the equilibrium concentrations are Keq = 1.5. The correct option is D.

<h3>What is Keq?</h3>

Keq is the ratio of the concentration of reactant to the concentration of the product.

The balanced equation is

N₂ + 3H₂  = 2NH₃

The equilibrium constant is \rm \dfrac{[NH_3]^2}{[N_2]\; [H_2]^3}

The given concentrations of the compounds have been:

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Learn more about Keq

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See below, please

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