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3 years ago

Provide at least three reasons why friction is needed.

2 answers:

8 0

Sample Response: Friction allows people and objects to move. It provides traction for an object to start moving or change direction. It can also give people a better grip on objects. Finally, friction keeps objects in place when they are set down.

-Friction makes movement possible.

-Friction provides traction

-Friction makes it easier to hold on to objects

-Friction keeps objects in place.

Anarel [89]3 years ago

6 0

Without friction, we would not be able to stop walking since we would just keep slipping like on ice.

Without friction, objects would just slip and fall with a simple blow of air

And finally without friction we wouldn't be able to use machinery like cars and etc since they would just fly off

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As an admirer of Thomas Young, you perform a double-slit experiment in his honor. You set your slits 1.15 mm apart and position

Artist 52 [7]

Answer:

The distance of the first bright fringe is given as $Y_C = 1.22 *10^{-3}m$

The distance of the second dark fringe from the central bright fringe is given as $Y_D = 0.00192 \ m$

Explanation:

From the question we are told that

The slit separation distance is $d = 1.15 mm = \frac{1.15}{1000} =0.00115 m$

The distance of the slit from the screen is $D = 3.23 m$

The wavelength is $\lambda = 633 nm$

For constructive interference to occur the distance between the two slit is mathematically represented as

$Y_C =\frac{m \lambda D}{d}$

Where m is the order of the fringe which has a value of 1 for first bright fringe

Substituting values

$Y_C = \frac{1 * 633 *0^{-9} * 3.23}{0.00115}$

$Y_C = 1.22 *10^{-3}m$

For destructive interference to occur the distance between the two slit is mathematically represented as

$Y_D = [n + \frac{1}{2} ] \frac{\lambda D}{d}$

m = 2

so the formula to get the dark fringe is $n = \frac{1}{2} * 1$

$n=1$

Now substituting values

$Y_D = [ 1 + \frac{1}{2} ] * \frac{633 *10^{-9} * 3.23 }{0.00115}$

$Y_D =1.5 * \frac{633 *10^{-9} * 3.23 }{0.00115}$

$Y_D = 0.00192 \ m$

4 0

3 years ago

In your experiment, you measure a total deflection of 4.12 cm when an electric field of 1.10×103V/m is established between the p

Bond [772]

Answer:

$B_0 = 1.69 \times 10^{-4}\ T$

Explanation:

given,

total deflection = 4.12 cm

Electric field = 1.1 ×10³ V/m

plate length = 6 cm

distance between them = 12 cm

using formula

$v_0 = \sqrt{\dfrac{q\epsilon_0d}{ym}(\dfrac{d}{2}+L)}$

q = 1.6 × 10⁻¹⁹ C

m = 9.11 x 10⁻³¹ kg

d = 0.06 m

L = 0.12 m

$v_0 = \sqrt{\dfrac{1.6 \times 10^{-19}\times 1.1 \times 10^{3}\times 0.06}{0.0412\times 9.11 \times 10^{-31} }(\dfrac{0.06}{2}+0.12)}$

v_0 = 6496355.63 m/s

$v_0 = \dfrac{E}{B_0}$

$B_0 = \dfrac{E}{v_0}$

$B_0 = \dfrac{1.1\times 10^{3}}{6496355.63}$

$B_0 = 1.69 \times 10^{-4}\ T$

5 0

3 years ago

The equation for density is mass divided by volume. the mass of a substance is changed so that it is made of fewer particles. If

Finger [1]

Density is directly proportional to mass. So if there's less matter inside object, its density will also reduce.

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A lightbulb is rated by the power that it dissipates when connected to a given voltage. For a lightbulb connected to 120 V house

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1. increase, 2. decrease

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3 years ago

In which situation is the gravitational force between two objects hard to detect? (Options)

svlad2 [7]

A - the objects are too small

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3 years ago

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