The answer to this question is false
<span>The answer is, 7.44 kg*m/s</span>
Answer:
a) 17 km
b) 9 km
Explanation:
The distance is the length of the path.
A to C: 5 km
B to C: 4 km
C to B: 4 km
B to C: 4 km
Total distance = 5 km + 4 km + 4 km + 4 km = 17 km
Displacement is the difference between the starting point and ending point.
Displacement = 9 km − 0 km = 9 km
Answer:
The tangential speed at Livermore is approximately 284.001 meters per second.
Explanation:
Let suppose that the Earth rotates at constant speed, the tangential speed (
), measured in meters per second, at Livermore (37.6819º N, 121º W) is determined by the following expression:
(1)
Where:
- Rotation time, measured in seconds.
- Radius of the Earth, measured in meters.
- Latitude of the city above the Equator, measured in sexagesimal degrees.
If we know that
,
and
, then the tangential speed at Livermore is:


The tangential speed at Livermore is approximately 284.001 meters per second.