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3 years ago

BRAINLIEST!! What did Robert Sternberg believe about intelligence?

2 answers:

4 0

The triarchic theory of intelligence was formulated by Robert J. Sternberg, a prominent figure in the research of human intelligence. The theory by itself was groundbreaking in that it was among the first to go against the psychometric approach to intelligence and take a more cognitive approach

Simora [160]3 years ago

3 0

These three examples exemplify Robert Sternberg's triarchic theory on intelligence. The triarchic theory describes three distinct types of intelligence that a person can possess. Sternberg calls these three types practical intelligence, creative intelligence, and analytical intelligence.

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An airplane starts from rest and reaches a takeoff velocity of 60.0m/s due north in 4.0s. How far has it traveled before take of

lions [1.4K]

Initial velocity, u = 0
Final velocity, v = 60 m/s (at take off)
Duration of the acceleration, t = 4 s

Calculate average acceleration.
a = (v - u)/t
= (60 m/s)/(4 s)
= 15 m/s²

Calculate the distance traveled during acceleration.
s = ut + (1/2)*a*t²
= 0.5*(15 m/s²)*(4 s)²
= 120 m

Answer: 120 m

3 0

3 years ago

Consider two massless springs connected in series. Spring 1 has a spring constant k1, and spring 2 has a spring constant k2. A c

Andru [333]

Answer:

a. k = (1/k₁ + 1/k₂)⁻¹ b. k = (1/k₁ + 1/k₂ + 1/k₃)⁻¹

Explanation:

Since only one force F acts, the force on spring with spring constant k₁ is F = k₁x₁ where x₁ is its extension

the force on spring with spring constant k₂ is F = k₂x₂ where x₁ is its extension

Let F = kx be the force on the equivalent spring with spring constant k and extension x.

The total extension , x = x₁ + x₂

x = F/k = F/k₁ + F/k₂

1/k = 1/k₁ + 1/k₂

k = (1/k₁ + 1/k₂)⁻¹

The force on spring with spring constant k₃ is F = k₃x₃ where x₃ is its extension

Let F = kx be the force on the equivalent spring with spring constant k and extension x.

The total extension , x = x₁ + x₂ + x₃

x = F/k = F/k₁ + F/k₂ + F/k₃

1/k = 1/k₁ + 1/k₂ + 1/k₃

k = (1/k₁ + 1/k₂ + 1/k₃)⁻¹

8 0

3 years ago

Read 2 more answers

I WILL MARK YOU THE BRAINLIEST NO LINKS What goes were put them in the correct place

PIT_PIT [208]

Answer:

Fluid fricton goes to Static friction and sliding friction goes to rolling friction

Explanation:

6 0

3 years ago

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Two identical metal spheres a and b are connected by a plastic rod. both are initially neutral. 1.0×1012 electrons are added to

Ann [662]

The plastic rod is made of insulator (plastic), so it does not allow charges moving from one sphere to another. This means that all the electrons given to sphere A will remain on sphere A.

The number of electrons initially given to sphere A is $N=1.0 \cdot 10^{12}$ , and since the charge of 1 electron is $e=-1.6 \cdot 10^{-19} C$ , the net charge left on sphere A after the removal of the rod will be
$Q=N e = 1.0 \cdot 10^{12}(-1.6 \cdot 10^{-19} C)=-1.6.0 \cdot 10^{-7} C$

8 0

3 years ago

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Two equipotential surfaces surround a +1.70 x 10-8-C point charge. How far is the 120-V surface from the 54.0-V surface?

UNO [17]

Answer:

1.55 m

Explanation:

The potential produced by a point charge, is inversely proportional to the distance from the charge to the point where the potential is being calculated, as follows:

$V =\frac{k*q}{r}$

As it only depends from the distance r, we can conclude that if the potential is the same for any point to a distance r from the point charge, the equipotencial surface must be a sphere of radius r.

Replacing q = +1.7*10⁻⁸ C, and k = 9*10⁹ N*m²/C², and V, by 120 V and 54 V, we can find the distance from the charge, to the points where we are calculating the potential V, as follows:

$r1 =\frac{k*q}{V1} = \frac{9e9 N*m2/C2*1.7e-8C}{120 V} = 1.28 m$

$r2 =\frac{k*q}{V2} = \frac{9e9 N*m2/C2*1.7e-8C}{54V} = 2.83 m$

The distance between both points, is just the difference between the radius of both spheres, as follows:

r₂ - r₁ = 1.55 m

5 0

3 years ago