The gravitational force on the woman is A) 500 N
Explanation:
There are two forces acting on the woman during her fall:
- The force of gravity,
, acting downward - The air resistance,
, acting upward
According to Newton's second law, the net force acting on the woman is equal to the product between the woman's mass and her acceleration:

where m is the mass of the woman and a her acceleration.
The net force can be written as

Also, we know that the woman falls at a constant velocity (5 m/s), this means that her acceleration is zero:

Combining the equations together, we get:

which means that the magnitude of the gravitational force is equal to the magnitude of the air resistance:

Learn more about forces and Newton's second law:
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Answer:

Explanation:
As we know that amplitude of forced oscillation is given as

here we know that natural frequency of the oscillation is given as

here mass of the object is given as



angular frequency of applied force is given as


now we have


Answer:
The maximum height is 2881.2 m.
Explanation:
Given that,
Acceleration = 29.4 m/s²
Time = 7.00 s
We need to calculate the distance
Using equation of motion

Put the value into the formula


We need to calculate the velocity
Using formula of velocity

Put the value into the formula


We need to calculate the height
Using formula of height

Put the value into the formula


We need to calculate the maximum height
Using formula for maximum height

Put the value into the formula


Hence, The maximum height is 2881.2 m.
All of the orbitals in a given subshell have the same value of the "<span>magnetic and principal" quantum number
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