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3 years ago

Consider the following equations of motion.

1 answer:

6 0

A) No, the equations presented above are the product of the derivation of position and velocity when the acceleration is constant.

The equations change to polynomial function of the second degree for the description of the acceleration when described as a function of time.

B) Yes, when the acceleration is zero it is concluded that the velocity is constant, therefore they could be used to describe the position as a function of the change in velocity.

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A sound wave has a speed of 330m/s and a wavelength of 0.372 m. what is the frequency of the wave?

Alja [10]

Answer:

887.1Hz

Explanation:

Given parameters:

Speed of sound wave = 330m/s

Wavelength = 0.372m

Unknown:

Frequency = ?

Solution:

To solve this problem, we use the expression below:

Speed = Frequency x wavelength

330 = Frequency x 0.372

Frequency = 887.1Hz

5 0

3 years ago

The membrane that surrounds a certain type of living cell has a surface area of 4.3 x 10-9 m2 and a thickness of 1.1 x 10-8 m. A

Nadusha1986 [10]

Answer:

The charge resides on the outer surface = $1.245 \times 10^{-12}$ C

Explanation:

Surface area of cell $(A) = 4.3\times 10^{-9} m^{2}$

Separation between two plate $(d) = 1.1 \times 10^{-8} m$

Dielectric constant $(k) = 4.2$

Potential difference $(\Delta V) = 85.7 \times 10^{-3} V$

The capacitance of parallel plate capacitor in free space is given by,

$C = \frac{\epsilon_{o} A }{d}$

Where $\epsilon_{o} =$ permittivity of free space = $8.85 \times 10^{-12}$

The Capacitance of capacitor is increase by $k$ times when it placed in dielectric medium.

$C_{dielectric} = \frac{k \epsilon_{o} A }{d}$

And we know that, $C = \frac{Q}{ \Delta V}$

So charge on the outer surface is given by,

$Q = \frac{k \epsilon A \Delta V }{d}$

$Q = \frac{4.2 \times 4.3 \times 10^{-9} \times 8.85 \times 10^{-12} \times 85.7\times 10^{-3} }{1.1 \times 10^{-8} }$

$Q = 1.245 \times 10^{-12}$

3 0

3 years ago

A wildlife researcher is tracking a flock of geese. The geese fly 4.0 km due west, then turn toward the north by 40º and fly ano

Kobotan [32]

Wildlife researcher starts from a and then reaches b, he turns towards north 40 degree to move towards c.

Total displacement is ac

Total horizontal displacement = 4+4 cos40 =7.06 km

Total vertical displacement = 4 sin40 =2.57 km

Total displacement $= \sqrt{7.06^2+2.57^2}$ = 7.51 km

7 0

3 years ago

Two capacitors have the same size of plates and the same distance 4 mm between the plates The potentials of the two plates in ca

OverLord2011 [107]

Answer:

E = -4000 N / C

Explanation:

The potential and electric field are related

V = - E s

E = - V / s

we reduce the magnitudes to the SI system

s = 4 mm (1 m / 1000 mm) = 0.004 m

we calculate

E = - 16 /0.004

E = -4000 N / C

8 0

3 years ago

About how far did the animal travel in 1 second

Stella [2.4K]

Answer:

one step UVU i dont even know XD there is no picture or graph?

Explanation:

7 0

3 years ago