All categories

3 years ago

When a hammer strikes a compound formed by covalent bonds, what will most likely happen to the compound?

Chemistry

2 answers:

Bess [88]3 years ago

8 0

Answer: Option (a) is the correct answer.

Explanation:

A compound formed by sharing of electrons is known as a covalent compound.

A covalent compound has weak intermolecular forces due to which it is brittle in nature. Hence, when we hit hammer on a covalent compound then it breaks easily.

Thus, we can conclude that when a hammer strikes a compound formed by covalent bonds, then most likely it will break into many pieces.

Step2247 [10]3 years ago

4 0

If its a solid it will stay and resist but if it isn´t then it will return to its original shape

You might be interested in

How much of strontium-90 will be left after 40 hours if you start with 960 grams and the half-life is 10 hours?

zmey [24]

Answer:

5 hours

Explanation:

7 0

2 years ago

The arrows in the chart below represent phase transitions. Three bars are shown labeled Solid, Liquid, and Gas. They are connect

tester [92]

Answer:

1,2,3

Explanation:

Heat gain implies that heat is absorbed by the system in order to make the stated phase transition possible.

Before a liquid changes to gas, intermolecular forces in the liquid are broken by energy supplied as heat.

Also, transition from solid to liquid requires energy to break intermolecular bonds.

Finally, sublimation requires input of energy in the form of heat.

4 0

3 years ago

Read 2 more answers

Wave particle duality is most apparent in analyzing the motion of.

DIA [1.3K]

Answer:

Wave particle duality is most apparent in analyzing the motion of. an electron. A photon of which electromagnetic radiation has the most energy.

5 0

2 years ago

What is the net ionic charge of a nitrogen ion? <br> +3 <br> -1 <br> -2 <br> -3

IgorLugansk [536]

-3 is the answer your looking for

8 0

3 years ago

Read 2 more answers

An unknown compound contains 38.7 % calcium, 19.9 % phosphorus and 41.2 % oxygen. what is the empirical formula of this compound

Softa [21]

Answer: Ca3(PO4)2

Explanation:

We assume that the sample is 100.0 g.

The sample contains 38.7 g of Ca, 19.9 g of P, and 41.2 g of O as the proportions show.

Then we can calculate the number of moles of each component (n = m/atomic mass).

The number of moles of Ca = 38.7/40.078 = 0.96 mol.

The number of moles of P = 19.9/30.97 = 0.64 mol.

The number of moles of O = 41.2/15.99 = 2.75 mol.

Now, we can get the molar ratios of different components (Ca, P, and O) in the sample by dividing the number of moles of each component by the lower number of moles, that we should divide the number of moles by (0.64).

Ca: P: O = (0.96/0.64) : (0.64/0.64) : (2.75/0.64) = 1.5 : 1 : 4.

To avoid the fraction of the ratios, we can multiply all ratios by 2.0.

Now, the ratio of Ca : P : O will be 3 : 2 : 8.

That main the empirical formula of the compound is Ca3P2O8 which can be expressed as calcium phosphate (Ca3(PO4)2).

8 0

3 years ago