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valentinak56 [21]
3 years ago
12

A photon has a wavelength of 750 no. What is the energy in joules

Chemistry
1 answer:
zhuklara [117]3 years ago
8 0

Answer:

750

Explanation:

750

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A 10.0 g pat of butter raise the water level in a graduated cylinder by 11.6 mL. What is the density of the butter
Nina [5.8K]

- formula for density is mass divided by volume

therefore density of butter = 10.0g divided by 11.6ml = 0.8620689 g/cm³ ≈ 0.862 g/cm³ (3sf)

8 0
3 years ago
What is the overall process of balancing an equation?
monitta

Answer:

You need to make sure the number of atoms of each element on the reactant side is equal to the number of atoms of each element on the product side. In order make both sides equal, you will need to multiply the number of atoms in each element until both sides are equal. :)

3 0
3 years ago
Q1.
valentinak56 [21]

Answer:

4.49dm3

Explanation:

2NH4Cl + Ca(OH)2 —> CaCl2 + 2NH3 + 2H2O

First, we need to convert 10g of ammonium chloride to mole. This is illustrated below:

Molar Mass of NH4Cl = 14 + (4x1) + 35.5 = 53.5g/mol

Mass of NH4Cl = 10g

Number of mole = Mass /Molar Mass

Number of mole of NH4Cl = 10/53.5 = 0.187mol

From the equation,

2moles of NH4Cl produced 2 moles of NH3.

Therefore, 0.187mol of NH4Cl will also produce 0.187mol of NH3

Now we can obtain the volume of NH3 produced by doing the following:

1mole of any gas occupy 24dm3

Therefore, 0.187mol of NH3 will occupy = 0.187 x 24 = 4.49dm3

4 0
3 years ago
Organic molecules always contain __________. carbon and oxygen oxygen and hydrogen carbon, hydrogen, and nitrogen carbon and hyd
ArbitrLikvidat [17]
Carbon and hydrogen atoms
5 0
3 years ago
At 25 oC, the rate constant for the first-order decomposition of a pesticide solution is 6.40 x 10-3 min-1. If the starting conc
Ira Lisetskai [31]

Answer:

2.11\ * 10^{-2}  is the correct answer to the given question.

Explanation:

Given k=6.40 x 10-3 min-1.

According to the first order reaction .

The concentration of time can be written as

[\ A\ ]\ = \ [\  A_{0}\ ]  * e \ ^\  {-kt}

Here [\ A\ ]_{0} = Initial concentration.

So  [\ A\ ]_{0}= 0.0314 M

Putting this value into the above equation.

0.0314 \ *\ e^{6.40 x 10^{-3} \ *  \ 62.0  }

=0.211 M

This can be written as

=\ 2.11 *\ 10^{-2}

3 0
3 years ago
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